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2 years ago

Please help me in this problem

Mathematics

1 answer:

Ivanshal [37]2 years ago

7 0

Answer:

asdlhbajkdsbjhadvbjafads

Step-by-step explanation:

aslikdhnlkdfnajksdbajksb c,mbdflkabn,m xcwmndb

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What are multiples of 6?

Savatey [412]

There are many I will some

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18
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3 years ago

A blimp provides aerial television views of a tennis game. The television camera sights the stadium at a 17degrees angle of depr

BaLLatris [955]

Answer:

1379.31meters is the line-of-sight distance from the television camera to the base of the stadium .

Step-by-step explanation:

As given

A blimp provides aerial television views of a tennis game.

The television camera sights the stadium at a 17degrees angle of depression. The altitude of the blimp is 400m.

Now by using the trignometric identity .

$sin\theta = \frac{Perpendicular}{Hypotenuse}$

As the figure is given below .

Perpendicular = AC = 400 m

Hypotenuse = AB

$\theta = 17^{\circ}$

Putting all the values in the identity .

$sin17^{\circ} = \frac{400}{AB}$

$0.29\ (Approx)= \frac{400}{AB}$

$AB= \frac{400}{0.29}$

AB = 1379.31 meters

Therefore the 1379.31 meters is the line-of-sight distance from the television camera to the base of the stadium .

3 0

3 years ago

Can I get help with 3 through 5

Nesterboy [21]

Answer: 3 is -4

Step-by-step explanation:

6 0

2 years ago

PLEASE HELP, IT WOULD BE MUCH APPRECIATED!! THANK YOU SO MUCH!! Do the graphs above show a relation, a function, both a relation

rewona [7]

Answer:

Well it definitely can't be a function

Step-by-step explanation:

To find out if a graph is a function, you can use the vertical line test. The vertical line test is when you draw a line down the center and if it hits one point, it's a function. But, when it hits more than one point, it's not. In this case, a line would hit more than one point; meaning that they are not functions.

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3 years ago

A line with slope -2/3 passes through the point (-12,16) What is the X-intercept

Troyanec [42]

to find the x-intercept of a function, we simply set y = 0 and then solve for "x", so, let's first find the equation of it and then set y = 0.

$\bf (\stackrel{x_1}{-12}~,~\stackrel{y_1}{16})~\hspace{10em} slope = m\implies-\cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-16=-\cfrac{2}{3}[x-(-12)] \\\\\\ y-16=-\cfrac{2}{3}(x+12)\implies \stackrel{\stackrel{y}{\downarrow }}{0}-16=-\cfrac{2}{3}x-8\implies -8=-\cfrac{2x}{3} \\\\\\ -24=-2x\implies \cfrac{-24}{-2}=x\implies 12=x \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill (12,0) ~\hfill$

4 0

3 years ago