Answer:
1,500 mm
Explanation:
if 1 meter = 1000 mm, 0.5 meters is 500 mm, so 1.50 meters is 1,500 mm
Answer:
Change in enthalpy for the reaction is -536 kJ
Explanation:
- Overall chemical reaction can be represented a summation of two given elementary steps with slight modification.
- Take reaction (1a) and divide stoichiometric coefficients by 2
- Take reverse reaction (2a) and divide stoichiometric coefficient by 2
- Then add these two modified elementary steps to get overall chemical reaction
is an additive property. hence value of
will be changed in accordance with modification


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Answer:
C-12 or C with a 12 superscripted on Upper left and 6 Subscripted on bottom left
Explanation:
Isotopic notation
Answer:
The answer is 18.12KJ is required to vaporise 48.7 g of dichloromethane at its boiling point
Explanation:
To solve the above question we have the given variable as follows
ΔHvap = heat of vaporisation of dichloromethane per mole = 31.6KJ/mole
However since the heat of vaporisation is the heat to vaporise one mole of dichloromethane, then, for 48.7 grams of dichloromethane, we have.
The number of moles of dichloromethane present = 48.7/84.93 = 0.573 moles
Therefore, the amount of heat required to vaporise 48.7 grams of dichloromethane at its boiling point is 31.6KJ/mole×0.573moles =18.12KJ
Answer:
<u>136.67 g of Na3PO4 i</u>s required to create 100 gram of NaOH.
Explanation:
The balanced equation:

1 mole Na3PO4 = 164 g/mole (Molar mass)
1 mole NaOH = 40 g/mole (Molar mass)
Now,
1 mole of Na3PO4 produce = 3 mole of NaOH
164 g/mol of Na3PO4 produce = 3(40) g/mol of NaOH
or
120 g/mol of NaOH is produced from = 164 g/mol of Na3PO4
1 g/mol of NaOH is produced from =

100 grams of NaOH is produced from =
gram of Na3PO4
calculate,
= 136.67 g