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1 year ago

7

The whole cloves are broken up to help release the eugenol during distillation.

1 answer:

GREYUIT [131]1 year ago

4 0

The statement is False.

No, whole cloves are not broken up to help release the eugenol during distillation.

Steam distillation:

Live steam is used in the co-distillation technique of steam distillation to separate mixture components.
It works well to extract essential oil constituents with high boiling points, such as those with boiling points of 200°C. However, the oil vapors themselves are warmer—around 100°C—helping to maintain the compounds' structural integrity.
It enables distillation to be carried out at lower temperatures than the boiling points of the constituent parts.
The high-boiling essential oils are vaporized by steam, and after passing through a cooling system, the hot vapors that were formed from them condense back into a liquid along with water.
A two-phase distillate, consisting of a water layer and an oil layer, is created because the oils are immiscible in water.

Learn more about the Steam distillation with the help of the given link:

brainly.com/question/14864901

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How many millimeters (mm) is the length of a standard table if it is

matrenka [14]

Answer:

1,500 mm

Explanation:

if 1 meter = 1000 mm, 0.5 meters is 500 mm, so 1.50 meters is 1,500 mm

5 0

2 years ago

In the following overall chemical reaction, aluminum displaces chromium from chromium(III) oxide and forms aluminum oxide.

mafiozo [28]

Answer:

Change in enthalpy for the reaction is -536 kJ

Explanation:

Overall chemical reaction can be represented a summation of two given elementary steps with slight modification.
Take reaction (1a) and divide stoichiometric coefficients by 2
Take reverse reaction (2a) and divide stoichiometric coefficient by 2
Then add these two modified elementary steps to get overall chemical reaction
$\Delta H$ is an additive property. hence value of $\Delta H$ will be changed in accordance with modification

$2Al+\frac{3}{2}O_{2}\rightarrow Al_{2}O_{3}.....\Delta H_{1}=\frac{-3351.4}{2}kJ=-1675.7kJ$

$Cr_{2}O_{3}\rightarrow 2Cr+\frac{3}{2}O_{2}....\Delta H_{2}=\frac{2279.4}{2}kJ=1139.7kJ$

--------------------------------------------------------------------------------------------------------------

$2Al+Cr_{2}O_{3}\rightarrow 2Cr+Al_{2}O_{3}....\Delta H=\Delta H_{1}+\Delta H_{2}=-1675.7+1139.7kJ=-536kJ$

6 0

3 years ago

Write the complete atomic structure for the Carbon atom. The atomic and mass numbers for carbon are 6 and 12 reapectively.

sergiy2304 [10]

Answer:

C-12 or C with a 12 superscripted on Upper left and 6 Subscripted on bottom left

Explanation:

Isotopic notation

4 0

2 years ago

How much energy is required to vaporize 48.7 g of dichloromethane (CH2Cl2) at its boiling point, if its ΔHvap is 31.6 kJ/mol?

BartSMP [9]

Answer:

The answer is 18.12KJ is required to vaporise 48.7 g of dichloromethane at its boiling point

Explanation:

To solve the above question we have the given variable as follows

ΔHvap = heat of vaporisation of dichloromethane per mole = 31.6KJ/mole

However since the heat of vaporisation is the heat to vaporise one mole of dichloromethane, then, for 48.7 grams of dichloromethane, we have.

The number of moles of dichloromethane present = 48.7/84.93 = 0.573 moles

Therefore, the amount of heat required to vaporise 48.7 grams of dichloromethane at its boiling point is 31.6KJ/mole×0.573moles =18.12KJ

3 0

3 years ago

1) Given the balance equation below. Calculate how much Na3PO4 in grams you

juin [17]

Answer:

<u>136.67 g of Na3PO4 i</u>s required to create 100 gram of NaOH.

Explanation:

The balanced equation:

$Na_{3}PO_{4} + 3 KOH \rightarrow 3 NaOH + K_{3}PO_{4}$

1 mole Na3PO4 = 164 g/mole (Molar mass)

1 mole NaOH = 40 g/mole (Molar mass)

Now,

1 mole of Na3PO4 produce = 3 mole of NaOH

164 g/mol of Na3PO4 produce = 3(40) g/mol of NaOH

or

120 g/mol of NaOH is produced from = 164 g/mol of Na3PO4

1 g/mol of NaOH is produced from =

$\frac{164}{120}$

100 grams of NaOH is produced from =

$\frac{164}{120}\times100$ gram of Na3PO4

calculate,

= 136.67 g

8 0

2 years ago