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lukranit [14]
3 years ago
5

On a distance vs. time graph of an object's motion, distance is usually

Physics
1 answer:
lozanna [386]3 years ago
5 0

Answer: the dependent variable  

a variable (often denoted by y ) whose value depends on that of another.  

hope it helps :]

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nevsk [136]

Answer:

2+2 =4

Explanation:

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3 years ago
Which one? A? B? C? D?
lidiya [134]

Answer:The answer is D.

Explanation:

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3 years ago
A tough kid on a tricycle has combined mass 32 kg. She starts from rest and travels 3.5 m in 2.5 s. What is the net force used t
Darina [25.2K]

Answer:

<h3>F = 35.84N</h3>

Explanation:

Force = mass * acceleration (Newton's second law of motion)

Given

Mass = 32kg

Get the acceleration using the expression d = 1/2at^2

3.5 = 1/2 (a)2.5^2

3.5 = 3.125a

a = 3.5/3.125

a = 1.12m/s^2

Get the net force;

F =  3.2 * 1.12

F = 35.84N

Hence the net force used to accelerate is 35.84N

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3 years ago
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Juliette [100K]

Answer:

Light slows down

Explanation:

8 0
3 years ago
An airplane pilot wishes to fly due west. A wind of 80.0 km/h (about 50 mi/h) is blowing toward the south. (a) If the airspeed o
Vesnalui [34]

Answer:

a) 75.5 degree relative to the North in north-west direction

b) 309.84 km/h

Explanation:

a)If the pilot wants to fly due west while there's wind of 80km/h due south. The north-component of the airplane velocity relative to the air must be equal to the wind speed to the south, 80km/h in order to counter balance it

So the pilot should head to the West-North direction at an angle of

cos(\alpha) = 80/320 = 0.25

\alpha = cos^{-1}(0.25) = 1.32 rad = 180\frac{1.32}{\pi} = 75.5^0 relative to the North-bound.

b) As the North component of the airplane velocity cancel out the wind south-bound speed. The speed of the plane over the ground would be the West component of the airplane velocity, which is

320sin(\alpha) = 320sin(75.5^0) = 309.84 km/h

7 0
3 years ago
Read 2 more answers
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