Answer:
N₂ = 503.8 N
Explanation:
given,
mass of bottom block = 37 Kg
mass of middle block = 18 Kg
mass of the top block = 16 Kg
force acting on the top block = 170 N
force on the block at top
N₁ be the normal force from block at middle
now,
N₁ = 170 + m g
N₁ = 170 + 16 x 9.8
now, force on block at middle
N₂ be the normal force exerted by the bottom block
N₂ = N₁ + m₂ g
N₂ = 326.8 + 18 x 9.8
N₂ = 503.8 N
hence, normal force by bottom block is equal to N₂ = 503.8 N
Answer: Vertical height of rocket is 824.24ft
Explanation: see attachment.
Opp/ Adj = Tan 70°
h/ 300 = Tan 70°
h= 300tan 70°
h = 824.24ft
Answer:
Hi... Potential energy is converted to kinetic energy and kinetic energy is converted to potential energy
A) Net horizontal force:
Fx= -35 + 25 + -10N
Net vertical force
Fy= 50 - 35 = 15N
Net force
F^2 = fX^2 +Fy^2
F= 18N
B.) Acceleration of system
a=18/5=3.6m/s^2
C). Equilibriant force must be equal to the net force above
F1= 18N
D.) Acceleration becomes half
a1= a/2 =1.8m/s^2
E.) Equilibrant force also doubles
F" = 2F' = 36N
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