We use the first equation of motion, to calculate the acceleration of the car
Here, v is final velocity and its value is 100 km/h = 100(1000/3600) = 27 .78 m/s and u is initial velocity as car accelerates from rest so its value zero and t is time taken and its value is given 4.80 s.
Therefore,
.
Now the magnitude of force,
.
Thus, the magnitude of force by passenger experience during the acceleration is 393 .52 \ N.
Answer:
Explanation:
Using the equation of motion to get the acceleration due to gravoty of the rock on the planet.
S = ut+ 1/2at² where;
S is the distance of the rock above the surface of the planet = 100m
u is the initial velocity = 15m/s
a is the acceleration due to gravity
t is the time taken by the rock to reach the ground = 10s
Since the rock is thrown upward the acceleration due to gravity will be negative i.e a= -g
The equation becomes S = ut- 1/2gt²
Substituting the given value to get the time t
100 = 15(10)- 1/2g(10)²
100 = 150-50g
100-150 = -50g
-50 = -50g
g = -50/-50
g = 1m/s²
<em>Hence the acceleration due to gravity of the rock when it is on Planet XX is 1m/s²</em>
Answer:
The right answer is ball b
Explanation:
I hope it is helpful for you
because when ball b knocking bricks over than it will not able to come back
The answer is a. divided by time