Actually the question is not clear. The Benefit of lifting using lever is that you can apply force in a convenient direction and you can use very less force to lift object by balancing the torque due to object.For example you want to lift a mass of 4N with a force 2N you can use a class 2 lever and maintain the ratio between the distances of the body and the point of application of force from the fulcrum to be 1:2.In any case balance the torque to get the required force.
Answer:
B. 0 degrees
Explanation:
The magnetic flux through a certain area enclosed by a loop of wire immersed in a region with magnetic field is given by:
where
B is the strength of the magnetic field
A is the area enclosed by the coil
is the angle between the direction of the magnetic field and the direction of the normal to the coil
From the equation above, we see that the magnetic flux is maximum when
So when the field is parallel to the normal to the coil (so, when it is perpendicular to the coil), therefore when:
So, the correct option is
B. 0 degrees
Answer:
h = 3.10 m
Explanation:
As we know that after each bounce it will lose its 11% of energy
So remaining energy after each bounce is 89%
so let say its initial energy is E
so after first bounce the energy is
after 2nd bounce the energy is
After third bounce the energy is
here initial energy is given as
now let say final height is "h" so after third bounce the energy is given as
now from above equation we have
Answer:
11.6532 x 10⁻¹¹ J or 7.3 MeV is given off
Explanation:
Mass of an alpha particle = 4.0026u, ∴ mass of three = 12.0078u
Find the difference in mass.
Mass of three alpha - Mass of Carbon nucleus
12.0078u - 12u = 0.0078u
Since 1u = 1.66 x 10⁻²⁷ kg
Therefore, 0.0078u = 1.2948 x 10⁻²⁷
Now that we know Mass(m) = 1.2948 x 10⁻²⁷ and Speed (c) 3 x 10⁸ m²s⁻²
Formular for Energy ==> E₀ = mc²
E = (1.2948 x 10⁻²⁷) (3 x 10⁸ m²s⁻²)²
E = (1.2948 x 10⁻²⁷) (9 x 10¹⁶) J
E = 11.6532 x 10⁻¹¹ J
Or, if you need your energy in MeV
1 MeV = 1.60x10⁻¹³ J
Just do the conversion by dividing 11.6532 x 10⁻¹¹ J by 1.60x10⁻¹³ J
It will give you 7.3 MeV
