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3 years ago

Single and bored :( I’m a girl my name is Tessa that’s me on my pfp

Chemistry

2 answers:

Troyanec [42]3 years ago

7 0

Answer:

You perty, pertier than me

Explanation:

(Im a girl too, so no one thinks Im being weird guy =) )

Olenka [21]3 years ago

5 0

Answer: lol

Explanation:

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How do you calculate the volume of a gas at STP given the number of moles of gas present

S_A_V [24]

The Ideal Gas Law states that pressure (P) × volume (V) is equal to the # of moles (n) of the gas × a constant (R) × temperature (T), such that the equation is:
PV = nRT
At standard temp and pressure (STP), the T is 0°C or 273.15K, the P is 1 atm or 760 torr, and the R constant is 0.0821. Therefore the equation, solved for V becomes: V = nRT/P, or V = n(0.0821)(273)/1, so that it reduces to V = 22.4 Liters, when n = 1 mole.
So the V of any gas at STP is 22.4 L / mole

8 0

4 years ago

If an element has more than one ionic charge, how is that piece of information represented in a chemical name?

Lostsunrise [7]

Usually with roman numerals, like iron (II) chromate
iron has a charge of 2
or manganese (IV) oxide, manganese has a charge of 4
(these are ionic compounds just to let you know)

3 0

3 years ago

A compound is composed of C, H and O. A 1.621 g sample of this compound was combusted, producing 1.902 g of water and 3.095 g of

vlada-n [284]

Answer: The molecular of the compound is, $C_2H_3O$

Explanation:

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

$C_xH_yO_z+O_2\rightarrow CO_2+H_2O$

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of $CO_2=3.095g$

Mass of $H_2O=1.902g$

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in $3.095g$ of carbon dioxide, $\frac{12}{44}\times 3.095=0.844g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

So, in $1.902g$ of water, $\frac{2}{18}\times 1.092=0.121g$ of hydrogen will be contained.

For calculating the mass of oxygen:

Mass of oxygen in the compound = $(1.621)-[(0.844)+(0.121)]=0.656g$

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{0.844g}{12g/mole}=0.0703moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.121g}{1g/mole}=0.121moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.656g}{16g/mole}=0.041moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is $0.041$ moles.

For Carbon = $\frac{0.0703}{0.041}=1.71\approx 2$

For Hydrogen = $\frac{0.121}{0.041}=2.95\approx 3$

For Oxygen = $\frac{0.041}{0.041}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 2 : 3 : 1

Hence, the empirical formula for the given compound is $C_2H_3O_1=C_2H_3O$

The empirical formula weight = 2(12) + 3(1) + 1(16) = 43 gram/eq

Now we have to calculate the molecular formula of the compound.

Formula used :

$n=\frac{\text{Molecular formula}}{\text{Empirical formula weight}}$

$n=\frac{46.06}{43}=1$

Molecular formula = $(C_2H_3O_1)_n=(C_2H_3O_1)_1=C_2H_3O$

Therefore, the molecular of the compound is, $C_2H_3O$

6 0

3 years ago

Santos and Lüderitz are the same distance from the equator, and both cities are near the ocean. The air temperature in Lüderitz

Svetach [21]

Answer:rjr

pie

xeplanation:jfffjfj

6 0

3 years ago

Read 3 more answers

Calculate the energy required to produce 9.00 mol of Cl₂O₇ based on the following balanced equation. 2Cl₂(g) + 7O₂(g) + 130 kcal

AleksandrR [38]

Answer:

585 kcal .

Explanation:

From the balanced equation:

2Cl₂(g) + 7O₂(g) + 130 kcal → 2Cl₂O₇.

130 kcal are needed to produce 2 mol of Cl₂O₇.

Using cross multiplication:

130 kcal are needed to produce → 2 mol of Cl₂O₇.

??? kcal are needed to produce → 9 mol of Cl₂O₇.

∴ The energy required to produce 9.00 mol of Cl₂O₇ = (130 kcal)(9 mol)/(2 mol) = 585 kcal.

6 0

3 years ago