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trapecia [35]
2 years ago
12

The planet Gallifrey has 2 times the gravitational field strength and 2 times the radius of the Earth.

Physics
1 answer:
Alexeev081 [22]2 years ago
4 0

The mass of the planet Gallifrey is 8 times the mass of the Earth.

  • let the gravitational field of Earth = g
  • let the radius of the Earth = R
  • gravitational field of Gallifrey = 2g
  • radius of Gallifrey = 2R

<h3>What is gravitational potential energy?</h3>
  • This is the work done in moving an object to a certain distance against gravitational field.

The gravitational field strength of the Earth is given as follows;

g = \frac{GM}{r^2} \\\\G = \frac{gr^2}{M}

The gravitational field strength of the Planet Gallifrey is calculated as follows;

g_2 = \frac{GM_2}{r_2^2}

G = \frac{g_2r_2^2}{M_2} \\\\\frac{g_2r_2^2}{M_2} = \frac{gr^2}{M}\\\\M_2gr^2 = Mg_2r_2^2\\\\M_2 = \frac{Mg_2r_2^2}{gr^2} \\\\M_2 = \frac{M \times 2g \times (2r)^2}{gr^2} \\\\M_2 = \frac{M \times 2g \times 4r^2}{gr^2} \\\\M_2 = 8M

Thus, the mass of the planet Gallifrey is 8 times the mass of the Earth.

Learn more about gravitational field strength here:  brainly.com/question/14080810

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Answer:

32.1

Explanation:

NOTE: You did not state the angle of incidence, and thus, I will be using 45° as my angle of incidence, all you need to do is replace it with your own value if it's different.

To solve this question, we are going to be using Snell's Law.

Snell's law describes the relationship between the angles of incidence and refraction, when referring to light or other waves passing through a boundary between two different isotropic media, such as water, glass, or air.

Snell's law is mathematically given as

sin(A1)/sin(A2) = n2/n1, where

n1 = incidence index

n2 = refracted index

A1 = incidence angle

A2 = refracted angle

The refraction index of oil is 1.15, and that of water is 1.33, so

if we take oil first,

sin A2 = (n1.sinA1)/n2

sin A2 = (1 * sin 45)/1.15

sin A2 = 0.7071/1.15

sin A2 = 0.6149

A2 = sin^-1 0.6149

A2 = 37.9°

Then

sin A3 = (1.15 * sin 37.9) / 1.33

sin A3 = (0.6149 * 1.15) / 1.33

sin A3 = 0.7071 / 1.33

sin A3 = 0.5317

A3 = sin^-1 0.5317

A3 = 32.1

4 0
3 years ago
An artillery shell is fired at a target 200 m above the ground. When the shell is 100 m in the air, it has a speed of 100 m/s. W
Marat540 [252]

Explanation:

Below is an attachment containing the solution.

3 0
3 years ago
A train travelled from city a to city b. For the first 14hours,it travelled at an average speed of 120km/h. For the 10 hours, it
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Explanation:

distance covered in the first part of journey : 120×14 = 1680km

distance covered in second part of journey :

90×10 = 900 km

total distance traveled : 1680+900 = 2580km.

total time taken to complete the journey : 14+10= 24 hrs.

therefore, the average speed of the journey = 2580km/24hr = 107.5 km/h.

hope this helps you.

4 0
2 years ago
A light plane must reach a speed of 33m/s for takeoff.how long a runway is needed if the the acceleration is 3.0m/s^2
Tanzania [10]

Remark

Always write down your givens and what you want to find. The formula you use for such questions will suggest itself if you do this.

Givens

a = 3.0 m/s^2

vi = 0  I presume that's that the question assumes.

vf = 33 m/s

You want d

Formula

vf^2 = vi^2 + 2*a*d

Solution

33^2 = 0^2 + 2 * 3 * d

1089 = 6*d

d = 1089/6

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