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3 years ago

Which, if any, of the heat engines violate(s) the second law of thermodynamics?

Physics

1 answer:

Anuta_ua [19.1K]3 years ago

3 0

The second law states that the total entropy can never decrese over time for an isolated system

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A cylindrical metal bar of diameter 14cm and length 484 cm is to be melted to make a metalic cube.if one side of the box is 220m

asambeis [7]

The number of boxes were produced willl be 7.57.n stands for the no of boxes.

<h3>What is volume?</h3>

The term “volume” refers to the amount of three-dimensional space taken up by an item or a closed surface. It is denoted by V and its SI unit is in cubic cm.

The volume of the cylindrical metal bar;

V₁=πr²h

V₁=3.4 × 7² × 484 cm

V₁=80,634.4 cm³

The one side of the box is,220mm(22 cm)

V₂ = a³

V₂ = (22)³

V₂ = 10,648 cm³

The no of boxes is found as;

n = V₁/V₂

n=80,634.4 cm³/10,648 cm³

n=7.57

Hence, the number of boxes were produced willl be 7.57

To learn more about the volume, refer to brainly.com/question/1578538

#SPJ2

5 0

2 years ago

At an instant when a soccer ball is in contact with the foot of the player kicking it, the horizontal or x component of the ball

Ymorist [56]

Answer:440.03 N

Explanation:

Given

horizontal component of acceleration $(a_x)=800 m/s^2$

vertical component of acceleration $(a_y)=880 m/s^2$

mass of ball =0.37 kg

Force in horizontal direction $=m\times a_x=0.37\times 800=296 N$

Force in vertical direction $=m\times a_y=0.37\times 880=325.6 N$

Therefore net force is

$F=F_x+F_y$

$|F|=\sqrt{296^2+325.6^2}$

|F|=440.03 N

5 0

3 years ago

A basketball player standing under the hoop shoots the ball straight up with an initial velocity of v0Part (a) What is the maxim

Mama L [17]

Answer:

Maximum height will be $h=\sqrt{\frac{v_0^2}{2g}}$

Explanation:

We have given initial velocity through which basketball is thrown $=v_0$

Acceleration due to gravity $=g\ m/sec^2$

At maximum height velocity will be zero

So final velocity v = 0 m /sec

According to third equation of motion $v^2=u^2+2gh$

$0^2=v_0^2-2gh$ ( Negative sign is due to upward acceleration )

$h=\sqrt{\frac{v_0^2}{2g}}$

6 0

3 years ago

Suppose that the magnetic field in some region has the form B = kz ˆx (where k is a constant). Find the force on a square loop (

AleksAgata [21]

Answer:

$F = ika^2$

Explanation:

As we know that loop is placed in YZ plane and magnetic field is along x direction

So here net force on the side of the loop which lies along Y axis is given as

$F_1 = i (\vec L \times \vec B)$

here we know that on Y axis z = 0

so B = 0

so we have

$F_1 = 0$

now on the opposite side we have z = a

so magnetic field is given as

$B = ka$

so force on that side is given as

$F = i(\vec L \times \vec B)$

$F = i(a)(ka) sin90$

$F_2 = ika^2$

so net force on the loop is given as

$F = F_1 + F_2$

$F = ika^2$

5 0

3 years ago

Enter the following expression in the answer box below: 2gλ3m−−−−√, where λ is the lowercase Greek letter lambda.

atroni [7]

Answer:

$\sqrt{\dfrac{2g\lambda^3}{m}}$

Explanation:

We can write the expression here, but the point of the problem seems to be to see if you can manipulate the controls on the answer box to reproduce that expression.

$\boxed{\sqrt{\dfrac{2g\lambda^3}{m}}}$

7 0

3 years ago