All categories

2 years ago

Write down the value of 8^-4/3

Mathematics

1 answer:

avanturin [10]2 years ago

6 0

Answer: 1/16

Step-by-step explanation:

You might be interested in

Work out the percentage change to 2 decimal places when a price of £57.99 is decreased to £49.99.

IRISSAK [1]

Answer:

Percentage change in price = 13.80%

Step-by-step explanation:

Given that:

Original price = £57.99

Decreased price = £49.99

Difference = Original price - Decreased price

Difference = 57.99 - 49.99

Difference = £8.00

Percent change = $\frac{Difference}{Original\ price}100$

Percent change = $\frac{8.00}{57.99}*100$

Percent change in price = 13.80%

Hence,

Percentage change = 13.80%

5 0

3 years ago

125.504587156 rounded to the nearest whole number

kipiarov [429]

Answer:

126

hope this helps

7 0

2 years ago

Read 2 more answers

Brian’s grandmother offered to give him a gift of 50% of the amount of money he saved in one year. His grandmother gave him $60.

Mice21 [21]

Answer:

$120

Step-by-step explanation:

7 0

2 years ago

can someone sub to my youttube channel pls, its called Yakobu, its the one with 90 subs, pls it would really help :)

Lisa [10]

Answer:

ok i did

Step-by-step explanation:

4 0

3 years ago

[calculus] the distance from the point (6, -4) to the circle <img src="https://tex.z-dn.net/?f=x%5E2%2By%5E2-8y%3D0" id="TexForm

stealth61 [152]

Answer:

Option C.

The distance from the point to the circle is 6 units

Step-by-step explanation:

we know that

The distance between the circle and the point will be the difference of the distance of the point from the center of circle and the radius of the circle

step 1

Find the center and radius of the circle

we have

$x^{2} +y^{2}-8y=0$

Convert to radius center form

Complete the square

$x^{2} +(y^{2}-8y+16)=0+16$

Rewrite as perfect squares

$x^{2} +(y-4)^{2}=16$

The center is the point (0,4)

The radius is

$r^{2}=16\\r=4\ units$

step 2

Find the distance of the point from the center of circle

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

(6,-4) and (0,4)

substitute the values

$d=\sqrt{(4+4)^{2}+(0-6)^{2}}$

$d=\sqrt{(8)^{2}+(-6)^{2}}$

$d=\sqrt{100}\ units$

$d=10\ units$

step 3

Find the difference of the distance of the point from the center of circle and the radius of the circle

$10\ units-4\ units=6\ units$

therefore

The distance from the point to the circle is 6 units

see the attached figure to better understand the problem

3 0

3 years ago