(x-h)^2 + (y-k)^2 = r^2 where h & k are the x,y values of the center point
(x + 1)^2 + (y-3)^2 = 4^2
<span>(x + 1)^2 + (y-3)^2 = 16</span>
This is basically a simple problem to understand. The only thing that needs to be done is to divide the mass of the sun by the mass of mercury. It will give the required result.
Number of times the mass of sun is greater than
the mass of mercury = 21.3525×102921.3525×1029/<span>328.5×1021328.5×1021
= </span><span>7.1783629e+15
I hope that this is the answer that you were looking for and it has come to your great help.</span>
Answer:
f = .39
Step-by-step explanation:
d (v) = 2.15 v^2 / (64.4 f)
v = 40
d = 138
substitute these in
138 = 2.15 (40)^2 / (64.4 *f)
simplify
138 = 2.15 (*1600) / (64.4 *f)
138 = 3440 / (64.4 *f)
multiply each side by 64.4f
138 * 64.4 f = 3440
8887.2 f = 3440
divide by 8887.2
8887.2 f /8887.2= 3440/8887.2
f=.38707
to the nearest hundredth
f = .39
