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S_A_V [24]
3 years ago
14

My phone is just 2 percent ba bye I need to go​

Chemistry
2 answers:
Crank3 years ago
4 0

Answer:

HAHAHA SINUNGALING 62% OR 52% Pa yan.

never [62]3 years ago
3 0
Go charge ur phone!!
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Since this reaction takes place in acidic solution, H2O(l) and H+(aq) will be involved in the reaction. Places for these species
maxonik [38]

Answer:

The balanced equation is given below:

SO4^2−(aq)+ Sn^2+(aq) + 4H^+(aq) → H2SO3(aq)+ Sn^4+(aq) + H2O(l)

The coefficients of the reactants are: 1, 1, 4

The coefficients of the products are: 1, 1, 1

Explanation:

Step 1:

The equation for the reaction. This is given below:

SO4^2−(aq)+ Sn^2+(aq) + –––→ H2SO3(aq)+ Sn^4+(aq) + –––

Step 2:

Inclusion of H+ and H2O into the equation. This is illustrated below:

SO4^2−(aq)+ Sn^2+(aq) + H^+(aq) → H2SO3(aq)+ Sn^4+(aq) + H2O(l)

Step 3:

Balancing the equation.

SO4^2−(aq)+ Sn^2+(aq) + H^+(aq) → H2SO3(aq)+ Sn^4+(aq) + H2O(l)

The above equation can be balanced as follow:

There are total 4 atoms of H on the right side and 1 atom on the left side. It can be balance by putting 4 in front of H^+ as shown below:

SO4^2−(aq)+ Sn^2+(aq) + 4H^+(aq) → H2SO3(aq)+ Sn^4+(aq) + H2O(l)

Now the equation is balanced.

The coefficients of the reactants are: 1, 1, 4

The coefficients of the products are: 1, 1, 1

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