The question is incomplete, so I tried to find a similar problem online. It is shown in the attached picture. The reaction is
PCl₃ + Cl₂ ⇆ PCl₅
Then, we use the ICE (Initial-Change-Excess) approach as follows:
PCl₃ + Cl₂ ⇆ PCl₅
I 0.5 0.5 0.3
C -x -x +x
E 0.5-x 0.5-x 0.3+x
Total pressure: 0.5 - x + 0.5 - x + 0.3 + x = 1.3
Kp = [PCl₅]/[PCl₃][Cl₂]
0.18 = (0.3+x)/(0.5-x)²
Solving for x,
x= 0.21
Partial pressures would be:
<em>PCl₃ = 0.5 - 0.21 = 0.29 atm</em><em>Cl₂ = 0.5 - 0.21 = 0.29 atm</em><em>PCl₅ = 0.3+0.21 = 0.51 atm</em>
Answer:
Pure iron is impermeable to air and water, so True.
Explanation:
When corroding, the oxide layer becomes permeable, but water and air cannot pass through pure iron.
I hope this helps! :)
The valence electrons are determined by the column that the element falls in.
Column 1 has 1 valence electron
Column 2 has 2 valence electrons
Column 13 has 3 valence electrons
Column 15 has 5 valence electrons
column 16 has 6 valence electrons
column 17 has 7 valence electrons
Elements are trying to become stable by filling the outer energy level. Columns 1,2,3 do this by losing 1,2 or 3 electrons and becoming positive ions. +1, +2, +3, respectively
Columns 15, 16, 17 do this by taking those electrons and becoming negative ions. -3, -2, -3. respectively.