A line segment from a vertex to the midpoint of the opposite side is a "median". A median divides the area of the triangle in half, as it divides the base in half without changing the altitude.
AAMC is half AABC. AADC is half AAMC, so is 1/4 of AABC. (By the formula for area of a triangle.)
ABMC is half AABC. ABMD is half ABMC, so is 1/4 of AABC. (By the formula for area of a triangle.)
Then, AADC = 1/4 AABC = ABMC, so AADC = ABMC by the transitive property of equality.

8 0

3 years ago

If p-4(p-2(3-p))=12 solve for p

stira [4]

P-4(p-2(3-p))=12 remove the parentheses

P-4(p-6+2p)=12 collect like terms

P-4(3p-6)=12 remove the parentheses

P-12p+24=12 collect like terms

-11p+24=12 move the constant to the right

-11p=12-24 calculate

-11p=-12 divide both sides

P=12/11

Alternative form

P=1 1/11

8 0

3 years ago