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seropon [69]
3 years ago
6

One hundred offices need to be painted .The workers choose between yellow ,blue or beige. They decide that 45% of the offices wi

ll be painted yellow 28% will be painted blue and the remaining offices will be painted beige create a model that shows the percent of offices that will be painted each color write the amount as decimals and fractions
Mathematics
1 answer:
cupoosta [38]3 years ago
6 0

Answer:

45% of offices painted yellow.

45% of 100 offices is 45.

45/100 is 0.45.

28% of offices painted blue.

28% of the 100 offices is 28.

28/100 is 0.28.

100%-28%-45%=27%

27% of offices painted beige.

27% of 100 offices is 27.

27/100 is 0.27.

Step-by-step explanation:

mark brainliest

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mariarad [96]

Answer:

3

Step-by-step explanation:

6x+2y=12

2y=6x-12

y=6x/2- 12/2

y=3x-6

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Roberto paid $43.08 for 3 cds. all 3 cds were the same price. how much did each cd cost
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Hey guys so im in a little trouble i need some help please. I got 3 i just need 4,5,6,7,8,9,10 please and also i need step by st
Minchanka [31]

Answer:

4. x= -6

5. x= 7

6. x= -18

7. x= 8

8. x= 7

I'll do 9 and 10 in a separate answer

Step-by-step explanation:

4. Multiplying a negative with another negative always equals a positive, so replace x with -6, multiply -6 and -3 and you'll get 18.

5. To make it simple, think "what minus 3 equals 11?" So in this case, multiplying 2 by 7 would = 14, and that minus 3 is 11.

6. Divide a negative by a positive to get a negative answer. -9 + 6 = -3, but first we have to get 9. So since the fraction is x divided by 2, you'd replace x with -18 to get -9.

7. -3 x 8 is -24, + 11 is -13.

8. What minus 7 equals 21? 28. So replace x with 7. (7 x 4 = 28), subtract 7 from 28, and then you'll have 21.

6 0
3 years ago
SHOW ALL WORK. <br><br>PLEASE HELP THIS DUE AT MIDNIGHT
MatroZZZ [7]
In the first question,
Total no. of classmates(asked by Theresa for vote)=n= 100
no. of classmates who say yes= 62
proportion= p = 62/100 = 0.62
To find the 95% confidence interval use the formula,
          ( p- z_{ \alpha /2}  \sqrt{ \frac{p(1-p)}{n} } ,  p+z_{ \alpha /2}  \sqrt{ \frac{p(1-p)}{n} }) 
 
here,
1-α=95%
1-α=0.95
α(significance level)=0.05
α/2= 0.025
 From statistics table,
At α/2=0.025  z value is 1.96

By putting the values in above equation,
         ( 0.62- (1.96) \sqrt{ \frac{0.62(1-0.62)}{100} } ,0.62+(1.96) \sqrt{ \frac{0.62(1-0.62)}{100} }
         =(0.5249, 0.715)

In the second question,
Total no. of highways=n= 125
no. of highways need to be repair= 75
proportion= p = 75/125 = 0.6
To find the 99% confidence interval use the formula,
          ( p- z_{ \alpha /2} \sqrt{ \frac{p(1-p)}{n} } , p+z_{ \alpha /2} \sqrt{ \frac{p(1-p)}{n} }) 
 
here,
1-α=99%
1-α=0.99
α(significance level)=0.01
α/2= 0.005
 From statistics table,
At α/2=0.005  z value is 2.576

By putting the values in above equation,
         ( 0.6- (2.576) \sqrt{ \frac{0.6(1-0.6)}{125} } ,0.6+(2.576) \sqrt{ \frac{0.6(1-0.6)}{125} }
         =(0.4871, 0.7129)

     
          
                       

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4 0
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