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marishachu [46]
3 years ago
10

Móvil A : V = 16 m/s ; t = 5 sMóvil B : V = 15 m/s ; t = 6 s Móvil C : V = 24 m/s ; t = 3 s Calcular la distancia que recorre ca

da móvil y ordenar de forma ascendente sus distancias
Physics
1 answer:
patriot [66]3 years ago
4 0

Answer:

dC = 72m < dA = 80m < dB = 90m

Explanation:

In order to calculate the distance traveled by each mobile, you use the following formula:

d=vt          (1)

d: distance traveled

v: speed of the car

t: time of the motion

You replace the values of v and t for each mobile:

mobile A:

d_A=v_At_A=(16m/s)(5s)=80m

mobile B:

d_B=v_Bt_B=(15m/s)(6s)=90m

mobile C:

d_C=v_Ct_C=(24m/s)(3s)=72m

Then, you obtain that he distances traveled by the mobiles show:

dC = 72m < dA = 80m < dB = 90m

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Answer:

v=0.04m/s\\

s=-28.592m\\

Explanation:

a = 3t-4

v(t)=\int\limits^t_0 {a(t)} \, dt =3/2*t^{2}-4t+v_0\\

if t=3.6s and initial velocity, v0,  is -5m/s

v=0.04m/s\\

s(t)=\int\limits^t_0 {v(t)} \, dt =1/2*t^{3}-2t^{2}+v_0*t+s_0\\

if t=3.6s and the initial displacement, s0, is -8m:

s=-28.592m\\

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3 years ago
A box slides down a ramp inclined at 24◦ to the horizontal with an acceleration of 1.7 m/s 2 . The acceleration of gravity is 9.
dsp73

Answer:

<h3>0.445</h3>

Explanation:

In friction, the coefficient of friction formula is expressed as;

\mu = \frac{F_f}{R}

Ff is the frictional force = Wsinθ

R is the reaction = Wcosθ

Substitute inti the equation;

\mu = \frac{Wsin \theta}{W cos\theta} \\\mu = \frac{sin \theta}{cos\theta} \\\mu = tan \theta

Given

θ = 24°

\mu = tan 24^0\\\mu = 0.445\\

Hence the coefficient of kinetic friction between the box and the ramp is 0.445

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3 years ago
What is the density of an object when volume is 80cm3 and mass is 40 g? Group of answer choices
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i think its dense

Explanation:

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Explanation:

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Answer:

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670 Kg.m/s

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Final momentum is also mv but v being westward direction, we take it negative

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