The identity of a metal that has a mass of 27.0g and a volume of 10.0cm is Aluminium. That is option B.
<h3>What is molar mass?</h3>
Molar mass is defined as the mass in grams of one mole of an element. This is measured in grams/mole of that substance.
The metal that is 27.0 g and a volume of 10.0 cm3 is aluminium because aluminium is 27 times heavier than 1/12th of the mass of carbon-12 atom.
Therefore, the identity of a metal that has a mass of 27.0g and a volume of 10.0cm is Aluminium.
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Answer:
(a) 133.33nm
(b) 600nm
(c) 7,600nm
Explanation:
The concentration of Y can be determined by using the formula:
![Y = \dfrac{[L]}{k_d+[L]}](https://tex.z-dn.net/?f=Y%20%3D%20%5Cdfrac%7B%5BL%5D%7D%7Bk_d%2B%5BL%5D%7D)
where;
[L] = concentration of the binding ligand.
kd = 400 nm
Thus:
When Y = 0.25; we get :
![0.25 = \dfrac{[L]}{400+[L]}](https://tex.z-dn.net/?f=0.25%20%3D%20%5Cdfrac%7B%5BL%5D%7D%7B400%2B%5BL%5D%7D)
0.25 (400 + [L]) = [L]
100 + 0.25[L] = [L]
100 = [L] - 0.25 [L]
100 = 0.75 [L]
[L] = 100/0.75
[L] = 133.33 nm
At, Y = 0.6
![0.6 = \dfrac{[L]}{400+[L]}](https://tex.z-dn.net/?f=0.6%20%3D%20%5Cdfrac%7B%5BL%5D%7D%7B400%2B%5BL%5D%7D)
0.6 (400 + [L]) = [L]
240 + 0.6[L] = [L]
240 = [L] - 0.6 [L]
240 = 0.4 [L]
[L] = 240/0.4
[L] = 600 nm
At, Y = 0.95
![0.95 = \dfrac{[L]}{400+[L]}](https://tex.z-dn.net/?f=0.95%20%3D%20%5Cdfrac%7B%5BL%5D%7D%7B400%2B%5BL%5D%7D)
0.95 (400 + [L]) = [L]
380 + 0.95[L] = [L]
380 = [L] - 0.95 [L]
380 = 0.05 [L]
[L] = 380/0.05
[L] = 7600 nm
Wym kingdom? I dont get it
The answer is atoms good luck