The downward force acting on an object in free fall is the force of
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This is an incomplete question, here is a complete question.
Consider the second-order decomposition of nitroysl chloride:
At 450 K the rate constant is 15.4 atm⁻¹s⁻¹. How much time (in s) is needed for NOCl originally at a partial pressure of 53 torr to decay to 10.6 torr?
Answer : The time needed for NOCl is, 2.52 seconds.
Explanation : Given,
Rate constant =
Initial partial pressure of NOCl = 56 torr = 0.0737 atm
final partial pressure of NOCl = 14.5 torr = 0.0191 atm
The expression used for second order kinetics is:
where,
k = rate constant
t = time
= concentration at time 't'
= initial concentration
As we know that,
Thus, the expression of second order kinetics will be:
As,
So, ............(1)
Now put all the given values in the above expression 1, we get:
Therefore, the time needed for NOCl is, 2.52 seconds.
Answer : The correct option is, Chlorine
Explanation :
The given elements are, Se, B, Ca, Cl
- Element is Selenium, Se
Atomic number = 34
Group number = 16
General Electronic configuration of the group number 16 elements is, .
The general configuration shows the number of valence electrons are present in the element.
The number of valence electrons present = 2 + 4 = 6
- Element is Boron, B
Atomic number = 5
Group number = 13
General Electronic configuration of the group number 13 elements is, .
The number of valence electrons present = 2 + 1 = 3
- Element is Calcium, Ca
Atomic number = 20
Group number = 2
General Electronic configuration of the group number 2 elements is, .
The number of valence electrons present = 2
- Element is Chlorine, Cl
Atomic number = 17
Group number = 17
General Electronic configuration of the group number 17 elements is, .
The number of valence electrons present = 2 + 5 = 7
From this we conclude that the chlorine is the element which has the greatest number of valence electrons available for bonding.
Hence, the correct option is, Chlorine.