Answer:
0.500 mole of Xe (g) occupies 11.2 L at STP.
General Formulas and Concepts:
<u>Gas Laws</u>
- STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K
<u>Stoichiometry</u>
- Mole ratio
- Dimensional Analysis
Explanation:
<u>Step 1: Define</u>
<em>Identify.</em>
0.500 mole Xe (g)
<u>Step 2: Convert</u>
- [DA] Set up:

- [DA] Evaluate:

Topic: AP Chemistry
Unit: Stoichiometry
To determine the k for the second condition, we use the Arrhenius equation which relates the rates of reaction at different temperatures. We do as follows:
ln k1/k2 = E / R (1/T2 - 1/T1) where E is the activation energy and R universal gas constant.
ln 1.80x10^-2 / k2 = 80000 / 8.314 ( 1/723.15 - 1/593.15)
k2 = 0.3325 L / mol-s
Mass of sodium thiosulfate
is 110. g
Volume of the solution is 350. mL
Calculating the moles of sodium thiosulfate:
= 0.696 mol
Converting the volume of solution to L:

Finding out the concentration of solution in molarity:

Answer:
the pressure exerted in pascals is 0.5 Pa
Explanation:
The computation of the pressure exerted in pascals is shown below:
As we know that
Pressure = force ÷ area
= 25 ÷ 50
= 0.5 Pa
Hence, the pressure exerted in pascals is 0.5 Pa
We simply applied the above formula so that the correct pressure could come
the answer of these question is weight