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Artist 52 [7]
2 years ago
13

A sample of a compound contains 30.0 g C and 5.05 g H. Its molar mass is 78.12 g/mol. What is the compound’s molecular formula?

Chemistry
1 answer:
aleksklad [387]2 years ago
8 0
You seems to look worried so i will answer your question.
The correct answer is C6H6 as it has a molar mass of 73.07 grams per mole and it is the sample of compound that sums up with <span>78.12 grams per mole.
CH has </span>13.02 grams per mole.<span>C2H2 has a molar mass of 26.04.

Hope this helps you : )
If have more questions feel free to ask me :D</span>
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When a solution of sodium hydroxide is mixed with iron (II) chloride, a green precipitate is formed. What is the balanced equati
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The balanced chemical equation for the reaction is:

2NaOH(aq) + FeCl₂(aq) --> 2NaCl(aq) + Fe(OH)₂(s)

<h3>What is a chemical equation? </h3>

Chemical equations are representations of chemical reactions using symbols and formula of the reactants and products.

The reactants are located on the left side while the products are located on the right side.

Reactants —> Products

The balancing of chemical equations follows the law of conservation of matter which states that matter can neither be created nor destroyed during a chemical reaction but can be transferred from one form to another.

<h3>How to write the balanced equation </h3>

Sodium hydroxide => NaOH

Iron (II) chloride => FeCl₂

2NaOH(aq) + FeCl₂(aq) --> 2NaCl(aq) + Fe(OH)₂(s)

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brainly.com/question/7181548

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Which of the given statements best represent what to do in the event of a spill of concentrated sulfuric acid.
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2 years ago
Bromine monochloride is synthesized using the reaction:
Sergeu [11.5K]

Answer:

11.72 grams

Explanation:

Let the equilibrium concentration of BrCl be y

Initial concentration of Br2 = number of moles ÷ volume = (0.979×1000/160) ÷ 199 = 0.031 M

Initial concentration of Cl2 = (1.075×1000/71) ÷ 199 = 0.076 M

From the equation of reaction

1 mole of Br2 reacted with 1 mole of Cl2 to form 2 moles of BrCl

Therefore, equilibrium concentration of Br2 = (0.031 - 0.5y) M while that of Cl2 = (0.076 - 0.5y) M

Kp = [BrCl]^2/[Br2][Cl2]

1.1×10^-4 = y^2/(0.031 - 0.5y)(0.076 - 0.5y)

y^2/0.002356-0.0535y+0.25y^2 = 0.00011

y^2/0.00011 = 0.002356-0.0536y+0.25y^2

9090.9y^2-0.25y^2+0.0536y-0.002356 = 0

9090.65y^2+0.0535y-0.002356 = 0

The value of y must be positive and is obtained using the quadratic formula

y = [-0.0535 + sqrt(0.0535^2 - 4×9090.65×-0.002356)] ÷ 2(9090.65) = 9.2025/18181.3 = 0.00051 M

Mass of BrCl = concentration×volume×MW = 0.00051×199×115.5 = 11.72 grams

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3 years ago
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