Answer: a) pH = 13.00 : basic
b) ![[H_3O^+]=1.0\times 10^{-12}](https://tex.z-dn.net/?f=%5BH_3O%5E%2B%5D%3D1.0%5Ctimes%2010%5E%7B-12%7D)
: basic
c) pOH = 5.00 : basic
d) ![[OH^-]=1.0\times 10^{-9}](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D1.0%5Ctimes%2010%5E%7B-9%7D)
: acidic
Explanation:
pH or pOH is the measure of acidity or alkalinity of a solution.
pH is calculated by taking negative logarithm of hydrogen ion concentration.
![pH=-\log [H_3O^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%20%5BH_3O%5E%2B%5D)
Acids have pH ranging from 1 to 6.9 and bases have pH ranging from 7.1 to 14.Neutral substances have pH of 7.
a) pH = 13.00
As pH is more than 7, the solution is basic.
b)
Putting in the values:
![pH=-\log[1.0\times 10^{-12}]](https://tex.z-dn.net/?f=pH%3D-%5Clog%5B1.0%5Ctimes%2010%5E%7B-12%7D%5D)
As pH is more than 7, the solution is basic.
c) pOH = 5.00
As pH is more than 7, the solution is basic.
d)
Putting in the values:
![pOH=-\log[1.0\times 10^{-9}]](https://tex.z-dn.net/?f=pOH%3D-%5Clog%5B1.0%5Ctimes%2010%5E%7B-9%7D%5D)
As pH is less than 7, the solution is acidic.
1) Chemical formula for propane is CH₃-CH₂-CH₃.
Propane is a three carbon alkane (acyclic saturated <span>hydrocarbon).
</span>2) Chemical formula for propanal is CH₃-CH₂-CH=O.
Propanal <span> is a </span>saturated<span> three carbon </span>aldehyde (have<span> a </span>carbonyl<span> center).
3) </span>Chemical formula for propanol is CH₃-CH₂-CH₂-OH.
1-propanol <span> is a </span><span>primary alcohol.
4) </span>Chemical formula for propanone is (CH₃)₂-C=O.
Propanone or acetone is <span>he simplest and smallest</span> ketone.
Diagram of the nuclear composition, electron configuration, chemical data, and valence orbitals of an atom of neodymium-144 (atomic number: 60), an isotope of this element. The nucleus consists of 60 protons (red) and 84 neutrons (orange). 60 electrons (white) successively occupy available electron shells (rings).
Answer:
0.1 M
Explanation:
The following data were obtained from the question:
Initial volume (V1) = 100 mL
Initial concentration (C1) = 0.5 M
Final volume (V2) = 500 mL
Final concentration (C2) =?
Using the dilution formula C1V1 = C2V2, the new concentration of the solution can be obtained as follow:
C1V1 = C2V2
0.5 × 100 = C2 × 500
50 = C2 × 500
Divide both side by 500
C2 = 50/500
C2 = 0.1 M
Therefore, the new concentration of the solution is 0.1 M
The answer is B. two chlorine atoms.
The chemical formula of the compound is BaCl2~
