Q,,,law of refraction ?

Can a body have momentum without energy?

mestny [16]

No it does not! As it is not moving?!

7 0

3 years ago

A photoelectric experiment is performed where green light with a wavelength of 546.1 nm is shined on a metal plate, creating a p

PtichkaEL [24]

Answer:

$\phi=1.55 [eV]$

Explanation:

We can use the work function equation for a photoelectric experiment:

$\phi=\frac{hc}{\lambda}-K_{max}$

h is the plank constant
c is the speed of light
λ is the wave length
K is the kinetic energy (or K=eΔV)

So we will have:

$\phi=\frac{hc}{\lambda}-e\Delta V$

$\phi=\frac{6.63*10^{-34}*3*10^{8}}{546.1*10^{-9}}-0.728eV$

$\phi=3.64*10^{-19}[J]-0.728 [eV]$

$\phi=(3.64*10^{-19}[J]*\frac{1eV}{1.6*10^{-19}[J]})-0.728 [eV]$

$\phi=2.28 [eV] - 0.728 [eV]$

$\phi=1.55 [eV]$

I hope it helps you!

8 0

4 years ago

Read 2 more answers

¿Por que es importante el estudio del cosmos?

Paraphin [41]

Esta disciplina nos permite saber y comprender cómo es el conjunto de todo lo que rodea al planeta tierra. Todas las civilizaciones que han existido a lo largo de la historia han tenido una visión de conjunto sobre el universo.

4 0

3 years ago

What is the maximum centripetal acceleration experienced by a person standing still on the surface of the Earth? Where must they

skelet666 [1.2K]

Answer:

The person must be located in the Equator Line. The maximum centripetal acceleration experienced by a person is 0.0337 meters per square second.

Explanation:

Physically speaking, the centripetal acceleration ( $a_{r}$ ), measured in meters per square second, experienced by a person is defined by the following expression:

$a_{r} = \omega^{2}\cdot r$ (1)

Where:

$\omega$ - Angular speed of the Earth, measured in radians per second.

$r$ - Distance perpendicular to the rotation axis, measured in meters.

Since rotation axis passes through poles and distance described above is directly proportional to centripetal acceleration. The person must be located in the Equator Line, which is equivalent to the radius of the planet.

In addition, the angular speed of the Earth can be calculated in terms of its period ( $T$ ), measured in seconds: