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3 years ago

Q,,,law of refraction ?

Physics

1 answer:

AleksandrR [38]3 years ago

5 0

Answer:

Answer is in the attachment

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3 years ago

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jeyben [28]

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3 years ago

A 25kg mass is suspended at the end of a horizontal, massless rope that extends from a wall on the left and from the end of a se

patriot [66]

<h2>Answer:20.97g N,32.63g N</h2>

Explanation:

We consider the forces at the knot.

The vertical forces are

$T_{2}Sin(50^{0}})$ is the vertical component of tension $T_{2}$ at the knot.

$-25g$ is the weight of the mass $25Kg$ acting downwards.

The horizontal forces are

$-T_{1}$ is the tension in the rope acting left.

$T_{2}Cos(50^{0})$ is the horizontal component of tension $T_{2}$ acting towards right.

Since the knot has no mass,it is always in equilibrium.

So,the sum of forces acting on it will be zero.

Balancing vertical forces gives,

$T_{2}Sin(50^{0}})$ $-25g=0$

$T_{2}$ = $32.63gN$

Balancing horizontal forces gives,

$T_{2}Cos(50^{0})$ $-T_{1}=0$

$T_{1}=32.63g\times Cos(50^{0})=20.97gN$

7 0

3 years ago

Read 2 more answers

If a gasoline engine has an efficiency of 21 percent and losses 780 J to the cooling system and exhaust during each cycle, how m

NISA [10]

As we know that efficiency of engine is given as

$efficiency = \frac{W}{Q_i}$

also we know that

$Q_i - Q_o = W$

given that

$Q_o = 780 J$

efficiency = 21%

now we have

$0.21 = \frac{Q_i - Q_o}{Q_i}$

$0.21 Q_i = Q_i - 780$

$0.79Q_i = 780$

$Q_i =987.3J$

now we have

$W = 987.3 - 780 = 207.3 J$

7 0

3 years ago

Q,,,law of refraction ?​

Q,,,law of refraction ?