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Shtirlitz [24]
3 years ago
12

1. In the context of the poem, what does it mean to feel alone? How can two people experience isolation despite living in the sa

me home and being in the same relationship? What effect does one’s expectations of a relationship have on feelings of isolation?
Physics
1 answer:
Bingel [31]3 years ago
3 0

hello

Explanation:

I haven't read the poem because you didn't attach it but here is my go at answering the question- although we find it hard to imagine being lonely while with others... if you lack emotional or intellectual connection even being physically near someone you are not mentally there

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How is science controlled by the governerment
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Answer:

the government's use and control of science. To clarify, I live in the U.S. I'm only interested in how the U.S. government dictates science. If you have any information or links that could educate me on this topic, I would be appreciative.

Explanation:

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D.  Equal to zero.

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A rock of mass 200 g is attached to a 0.75 m long string and swung in a vertical plane.
Ainat [17]

Hello!

a) Assuming this is asking for the minimum speed for the rock to make the full circle, we must find the minimum speed necessary for the rock to continue moving in a circular path when it's at the top of the circle.

At the top of the circle, we have:

- Force of gravity (downward)

*Although the rock is still connected to the string, if the rock is swinging at the minimum speed required, there will be no tension in the string.

Therefore, only the force of gravity produces the net centripetal force:

\Sigma F = F_g\\\\F_c = F_g\\\\\frac{mv^2}{r} = mg

We can simplify and rearrange the equation to solve for 'v'.

\frac{v^2}{r} = g\\\\v^2 = gr\\\\v = \sqrt{gr}

Plugging in values:

v = \sqrt{9.8 * 0.75} = \boxed{2.711 m/s^}

b)
Let's do a summation of forces at the bottom of the swing. We have:
- Force due to gravity (downward, -)

- Tension force (upward, +)

The sum of these forces produces a centripetal force, upward (+).

\Sigma F = T - F_g\\\\F_c = T - F_g\\\\\frac{mv^2}{r} = T - mg

Rearranging for 'T":
T =   \frac{mv^2}{r} +  mg\\\\

Plugging in the appropriate values:
T =  \frac{(0.2)(2.711^2)}{(0.75)} + 0.2(9.8) = \boxed{3.92 N}

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2 years ago
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