Okay so you have to find acceleration first. I used v=vo+at. Plug in the numbers and you get -11.9m/s^2 as your constant acceleration. Then plug acceleration into d=vi(t)+1/2(a)t^2
d=(40m/s)(3.34s)+1/2(-11.9m/s^2)(3.34s)^2
d=68.6m
- Weight (W) = 110 N
- Acceleration due to gravity (g) = 9.8 m/s^2
- Let the mass of the object be m.
- By using the formula, W = mg, we get,
- 110 N = 9.8 m/s^2 × m
- or, m = 110 N ÷ 9.8 m/s^2
- or, m = 11.2 Kg
<u>Answer:</u>
<em><u>The </u></em><em><u>mass </u></em><em><u>of </u></em><em><u>the </u></em><em><u>object </u></em><em><u>is </u></em><em><u>1</u></em><em><u>1</u></em><em><u>.</u></em><em><u>2</u></em><em><u> </u></em><em><u>Kg.</u></em>
Hope you could get an idea from here.
Doubt clarification - use comment section.
The average velocity of the jet during the diversion is 518.75 m/s.
<h3>
Displacement of the pilot</h3>
The displacement of the pilot from the starting position is calculated as follows;
d² = 20² + 60² - 2(20)(60) x cos(θ)
where;
- θ is the angle between 20 km and 60 km leg of triangle formed from the motion.
θ = (90 - 38) + (90 - 55) = 87⁰
d² = 20² + 60² - 2(20)(60) x cos(87)
d² = 3874.39
d = 62.25 km
<h3>Average velocity of the pilot</h3>
V = total displacement/total time
where;
- time = 2mins = 0.033 hour
V = (62.25 km)/(0.033 hr)
V = 1,867.5 km/hr = 518.75 m/s
Thus, the average velocity of the jet during the diversion is 518.75 m/s.
Learn more about average velocity here: brainly.com/question/6504879
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Answer:
Explanation:
Y = 5 Sin27( .2x-3t)
= 5 Sin(5.4x - 81 t )
Amplitude = 5 m
Angular frequency ω = 81
frequency = ω / 2π
= 81 / (2 x 3.14 )
=12.89
Wave length λ = 2π / k ,
k = 5.4
λ = 2π / 5.4
= 1.163 m
Phase velocity =ω / k
= 81 / 5.4
15 m / s.
The wave is travelling in + ve x - direction.