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harkovskaia [24]
3 years ago
7

look at picture, need to know net force, whether they are balanced or unbalanced and whether they are accelerated or not acceler

ated!

Physics
1 answer:
kogti [31]3 years ago
7 0

Answer:

1) 100 ...unb. and accelerate

2) 7...unb. and accelerate

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Which processes result in the release of carbon? Select three options.
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Answer:

The remains of producers are broken down by decomposers.

The remains of consumers are broken down by soil decomposers.

Animals break down food molecules to obtain energy.

Explanation:

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Which biome's yearly rainfall mainly evaporates? A. taiga B. desert C. tropical rainforest D. temperate grassland
victus00 [196]
Desert is the correct answer.
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3 years ago
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Blood is accelerated from rest to 30.0 cm/s in a distance of 1.80 cm by the left ventricle of the heart. (a) Make a sketch of th
Mila [183]

Answer:

a. Picture attached

b. V, X

c. t=0.12 s

d. It makes sense cosidering that a normal heart beat rate is between 60 and 100 beats per minute (bpm).

Explanation:

First we have to identify the unknown of this problem:

a: acceleration\\t: time

Considering the characteristics of the problem and that distance and velocity are specified, the acceleration is constant, for that reason we use the equations of uniformly accelerated motion as follows:

v=v_{0}+at\\ x=x_{0}+ v_{0}+\frac{1}{2}at^{2}

If we reorganize the equations, considering that x_{0} and v_{0} are zero because motion starts from rest , we have:

a=\frac{v}{t} \\x=\frac{1}{2}at^{2}  =\frac{1}{2}\frac{v}{t} t^{2}=\frac{1}{2} vt\\t=\frac{2x}{v} \\t=\frac{2*1.80cm}{30.0\frac{cm}{s} } \\t=0.12 s

Finally, the analysis of the result leaves us to understand why the normal heart beat rate varies between 60 and 100 bpm.

6 0
3 years ago
How much work is done when 0.0050 c is moved through a potential difference of 9.0 v? use w = qv?
quester [9]

Answer:

0.045 J

Explanation:

The work done on a charge moving through a potential difference is given by

W=q\Delta V

where

W is the work done

q is the charge

\Delta V is the potential difference

In this problem, we have

q = 0.0050 C is the charge

\Delta V=9.0 V is the potential difference

Using the formula, we find the work done:

W=(0.0050 C)(9.0 V)=0.045 J

4 0
3 years ago
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How much work does the electric field do in moving a -7.7 hC charge from the ground to a point whose potential is +55 V higher?
Oduvanchick [21]
I really don’t know I just need some points to help me though this test I’m very sorry
7 0
3 years ago
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