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AfilCa [17]
3 years ago
5

Explain how the total pressure of a mixture of gases is determined.

Chemistry
1 answer:
WARRIOR [948]3 years ago
7 0

Answer:

The total pressure of a mixture of gases can be defined as the sum of the pressures of each individual gas: Ptotal=P1+P2+… +Pn. + P n . The partial pressure of an individual gas is equal to the total pressure multiplied by the mole fraction of that gas.

Explanation:

<h2><u>make it sound a little like you</u></h2>
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An ice cube floats in warm water in a container placed outside on a hot, sunny day.
SCORPION-xisa [38]

Answer:

Firsthand association assigns energy throughout conduction. Radiation transpires when particles consume energy that progresses as a wave. The heat will run from the h2O to the ice continuously until the ice has absolutely melted so both elements have reached the same temperature.

Explanation:

3 0
3 years ago
A steel tank with a volume of 2.15 L contains N2 gas under a pressure of 8.91 atm at 5.81°C. Calculate the number of moles of N2
Oksana_A [137]

Answer:

The answer to your question is   n = 0.838 moles

Explanation:

Data

Volume = 2.15 l

Pressure = 8.91 atm

Temperature = 5.81°C

moles = ?

Gas constant = 0.082 atm l / mol°K

Process

1.- Convert temperature to °K

Temperature = 5.81 + 273 = 278.81°K

2.- Write the Ideal gas formula

              PV = nRT

-Solve for moles (n)

              n = PV / RT

3.- Substitution

              n = (8.91 x 2.15) / (0.082 x 278.81)

4.- Simplification

               n = 19.16 / 22.86

5.- Result

               n = 0.838 moles

3 0
4 years ago
A lead ball is added to a graduated cylinder containing 41.7 ml of water, causing the level of the water to increase to 96.0 mL.
rjkz [21]

Answer:

Vlead ball=54.3 mL

Explanation:

The graduated cylinder contains 41.7mL of water

mL is a volume unit.

Water volume = 41.7 mL

The lead ball caused an increase of volume from 41.7 mL to 96.0 mL

The new volume is the lead ball volume plus the original water volume :

Final volume = Vlead ball+ Water original volume

96.0mL=Vleadball +41.7mL

Vlead ball=96.0mL-41.7mL

Vleadball=54.3mL

This is actually true if we suppose that the lead ball is fully sunken in the water.

We always must consider that the volume difference is the volume that the sunken object is occupying in the water.

5 0
3 years ago
How many grams are needed to form 33.6 L of carbon dioxide
pychu [463]
It depends of the temperature and the pressure. If temperature and pressure are standard 1 mol forms 22.4 liter. So 33.6 liters form 33.6/22.4 = 1.5 mols.

Now calculate the molar mass of carbon dioxide: 12 g/mol + 2x16 g/mol = 44 g/mol

The mass of the 1.5 mols is 1.5mol * 44 g/mol = 66 g.
7 0
3 years ago
help asap show work | a gas with a volume of 13L at a pressure of 197 kPA is allowed to expand to a volume of 23L. what is the p
Lera25 [3.4K]

Answer:

<h2>111 kPa</h2>

Explanation:

The new pressure can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we're finding the new pressure

P_2 =  \frac{P_1V_1}{V_2}  \\

We have

P_2 =  \frac{13 \times 197000}{23}  =  \frac{2561000}{23}  \\  = 111347.826...

We have the final answer as

<h3>111 kPa </h3>

Hope this helps you

5 0
3 years ago
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