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3 years ago

Explain how the total pressure of a mixture of gases is determined.

Chemistry

1 answer:

WARRIOR [948]3 years ago

7 0

Answer:

The total pressure of a mixture of gases can be defined as the sum of the pressures of each individual gas: Ptotal=P1+P2+… +Pn. + P n . The partial pressure of an individual gas is equal to the total pressure multiplied by the mole fraction of that gas.

Explanation:

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An ice cube floats in warm water in a container placed outside on a hot, sunny day.

SCORPION-xisa [38]

Answer:

Firsthand association assigns energy throughout conduction. Radiation transpires when particles consume energy that progresses as a wave. The heat will run from the h2O to the ice continuously until the ice has absolutely melted so both elements have reached the same temperature.

Explanation:

3 0

3 years ago

A steel tank with a volume of 2.15 L contains N2 gas under a pressure of 8.91 atm at 5.81°C. Calculate the number of moles of N2

Oksana_A [137]

Answer:

The answer to your question is n = 0.838 moles

Explanation:

Data

Volume = 2.15 l

Pressure = 8.91 atm

Temperature = 5.81°C

moles = ?

Gas constant = 0.082 atm l / mol°K

Process

1.- Convert temperature to °K

Temperature = 5.81 + 273 = 278.81°K

2.- Write the Ideal gas formula

PV = nRT

-Solve for moles (n)

n = PV / RT

3.- Substitution

n = (8.91 x 2.15) / (0.082 x 278.81)

4.- Simplification

n = 19.16 / 22.86

5.- Result

n = 0.838 moles

3 0

4 years ago

A lead ball is added to a graduated cylinder containing 41.7 ml of water, causing the level of the water to increase to 96.0 mL.

rjkz [21]

Answer:

$Vlead ball=54.3 mL$

Explanation:

The graduated cylinder contains $41.7mL$ of water

mL is a volume unit.

Water volume = 41.7 mL

The lead ball caused an increase of volume from 41.7 mL to 96.0 mL

The new volume is the lead ball volume plus the original water volume :

Final volume = Vlead ball+ Water original volume

$96.0mL=Vleadball +41.7mL$

$Vlead ball=96.0mL-41.7mL$

$Vleadball=54.3mL$

This is actually true if we suppose that the lead ball is fully sunken in the water.

We always must consider that the volume difference is the volume that the sunken object is occupying in the water.

5 0

3 years ago

How many grams are needed to form 33.6 L of carbon dioxide

pychu [463]

It depends of the temperature and the pressure. If temperature and pressure are standard 1 mol forms 22.4 liter. So 33.6 liters form 33.6/22.4 = 1.5 mols.

Now calculate the molar mass of carbon dioxide: 12 g/mol + 2x16 g/mol = 44 g/mol

The mass of the 1.5 mols is 1.5mol * 44 g/mol = 66 g.

7 0

3 years ago

help asap show work | a gas with a volume of 13L at a pressure of 197 kPA is allowed to expand to a volume of 23L. what is the p

Lera25 [3.4K]

Answer:

Explanation:

The new pressure can be found by using the formula for Boyle's law which is

$P_1V_1 = P_2V_2$

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we're finding the new pressure

$P_2 = \frac{P_1V_1}{V_2} \\$

We have

$P_2 = \frac{13 \times 197000}{23} = \frac{2561000}{23} \\ = 111347.826...$

We have the final answer as

Hope this helps you

5 0

3 years ago