Answer:
Volume of the helium will be 1.0L
Explanation:
To understand this question it is necessary to talk about 2 laws:
Charles's law that states: The volume of a given amount of gas held at constant pressure is directly proportional to absolute temperature.
Boyle's law that states: The volume of a given amount of gas held at constant temperature varies inversely with the applied pressure when the temperature and mass are constant.
Now, in the problem, if you have 4.0L of helium:
If the temperature is halved and the volume varies directly with temperature (Charles's law), the volume of helium will be 2.0L
Then, the pressure es doubled and as volume varies inversely with pressure (Boyle's law), the volume of helium will be halved, being 1.0L.
Thus, <em>volume of the helium will be 1.0L</em>
Answer:
Sodium oxide + Water - - - > Sodium Hydroxide.
Answer:I think this is right: 1. 6 2. 12 3. 4 4. In the middle 5. Carbon 1. The one on the right 2a. Beryllium 2b. Aluminium
Explanation:The protons are the circles with plus signs and the black ones are nutrons. I looked on my periodic table for the rest.
Answer:
294 moles of P
Explanation:
For every 1 mol of P4O10 contains 4 mol of P
so;
73.5 mol P4O10 × <u> </u><u> </u><u> </u><u> </u><u> </u><u>4 mol P</u><u> </u><u> </u><u> </u><u> </u><u> </u>
1 mol P4O10
= 73.5 × 4
= 294 moles of P
Answer : The solubility of this compound in g/L is
.
Solution : Given,

Molar mass of
= 114.945g/mole
The balanced equilibrium reaction is,

At equilibrium s s
The expression for solubility constant is,
![K_{sp}=[Mn^{2+}][CO^{2-}_3]](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BMn%5E%7B2%2B%7D%5D%5BCO%5E%7B2-%7D_3%5D)
Now put the given values in this expression, we get

The value of 's' is the molar concentration of manganese ion and carbonate ion.
Now we have to calculate the solubility in terms of g/L multiplying by the Molar mass of the given compound.

Therefore, the solubility of this compound in g/L is
.