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Lemon juice has a pH of about 2.0, compared with a pH of about 1.0 for stomach acid. Therefore, the concentration of H in stomac

Tamiku [17]

Answer: the concentration of H in the stomach acid is greater than that of the lemon juice

Explanation:Please see attachment for explanation

8 0

4 years ago

How many grams Glycylglycine (molecular mass 132.119 grams/mole) are required to make 1 liter at 0.5 Molar concentration. If you

SOVA2 [1]

Explanation:

The given data is as follows.

Concentration of solution = 0.5 M

Volume of solution = 1 L

Molar mass of Glycylglycine = 132.119 g/mol

As molarity is the number of moles present in liter of solvent.

Mathematically, Molarity = $\frac{\text{No. of moles}}{\text{Volume}}$

Hence, calculate the number of moles as follows.

No. of moles = Molarity × Volume

= $0.5 M \times 1 L$

= 0.5 mol

Therefore, mass of glycylglycine = mol × molar mass

= $0.5 mol \times 132.119 g/mol$

= 66.06 g

Thus, we can conclude that 66.06 g glycylglycine is required.

8 0

4 years ago

A first-order decomposition reaction has a rate constant of 0.00440 yr−1. How long does it take for [reactant] to reach 12.5% of

mina [271]

Answer:

473 year

Explanation:

Using integrated rate law for first order kinetics as:

$[A_t]=[A_0]e^{-kt}$

Where,

$[A_t]$ is the concentration at time t

$[A_0]$ is the initial concentration

Given:

To reach 12.5% of reactant means that 0.125 of $[A_0]$ is decomposed. So,

$\frac {[A_t]}{[A_0]}$ = 0.125

t = ?

$\frac {[A_t]}{[A_0]}=e^{-k\times t}$

$0.125=e^{-0.00440\times t}$

t = 473 year

8 0

3 years ago

Describe 5 importance matter to undergo changes

Rzqust [24]

Answer:

melting, freezing, sublimation, deposition, condensation, and vaporization. These changes

Explanation:

hope it helps...i dont know if its right but i hope it helps

3 0

3 years ago

How much heat is needed to condense 22.25 grams of nitrogen gas at â€""195.8Â°c? the latent heat of vaporization of nitrogen is

Margaret [11]

As per the question, the mass of the nitrogen gas m = 22.25 gram.

The latent heat of vaporization of nitrogen = 199.0 j/g

As per the question, the nitrogen gas will condense. During condensation, the nitrogen gas will lose or release heat equal to its latent heat.

Hence, the heat released by nitrogen gas Q = ml = 22.25 × 199.0 J = 4427.75 J.

Hence, the amount of heat released will be 4427.75 J.

<h3>How can you figure out how much heat is in each gram?</h3>

The formula: can be utilized to determine energy. Q = mc ∆T. In the equation, Q stands for energy expressed in joules or calories, m for mass expressed in grams, c for specific heat, and T for temperature change, which is the difference between the final temperature and the initial temperature. Water has a specific heat of 1 calorie/gram °C.

Learn more about energy here:

brainly.com/question/1932868

#SPJ4

8 0

1 year ago