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Inga [223]
1 year ago
8

How much heat is needed to condense 22.25 grams of nitrogen gas at â€""195.8°c? the latent heat of vaporization of nitrogen is

199.0 j/g. joules
Chemistry
1 answer:
Margaret [11]1 year ago
8 0

As per the question, the mass of the nitrogen gas m = 22.25 gram.

The latent heat of vaporization of nitrogen = 199.0 j/g

As per the question, the nitrogen gas will condense. During condensation, the nitrogen gas will lose or release heat equal to its latent heat.

Hence, the heat released by nitrogen gas Q = ml = 22.25 × 199.0 J                                                                           = 4427.75 J.

Hence, the amount of heat released will be 4427.75 J.

<h3>How can you figure out how much heat is in each gram?</h3>

The formula: can be utilized to determine energy. Q = mc ∆T. In the equation, Q stands for energy expressed in joules or calories, m for mass expressed in grams, c for specific heat, and T for temperature change, which is the difference between the final temperature and the initial temperature. Water has a specific heat of 1 calorie/gram °C.

Learn more about energy here:

brainly.com/question/1932868

#SPJ4

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How many moles are contained in a 4.67-l sample of gas at 30°c and 199 kpa?
ohaa [14]
Pv=nRT
where,p=199, R(constant)=8.314, V=4.67 T=30C=293K
n=pv/RT=0.38 moles
4 0
3 years ago
Read 2 more answers
If 0.25 mol of HClO2 is added to enough water to prepare a 0.25 M HClO2 aqueous solution, what is the concentration of H3O+(aq)
hammer [34]

Answer:

The concentration of H3O+= 0.15M

Explanation:

From The equation of reaction

HClO2(aq) + H2O(l) ⇌ H3O+(aq) + ClO2−(aq)

0.25mol HClO2(aq) 0.25mol producesClO2−(aq) and x-mol of H3O+

Using Kc = [H3O+][ClO2-]/[HClO2]

0.15= 0.25*x/0.25

Simplify

x=0.15M

5 0
3 years ago
Tritium 3 1H decays to 3 2He by beta emission. Find the energy released in the process. Answer in units of keV.
-Dominant- [34]

Answer:

The energy released in the decay process = 18.63 keV

Explanation:

To solve this question, we have to calculate the binding energy of each isotope and then take the difference.

The mass of Tritium = 3.016049 amu.

So,the binding energy of Tritium =  3.016049 *931.494 MeV

= 2809.43155 MeV.

The mass of Helium 3 = 3.016029 amu.

So, the binding energy of Helium 3 = 3.016029 * 931.494 MeV

= 2809.41292 MeV.

The difference between the binding energy of Tritium and the binding energy of Helium is: 32809.43155 - 2809.412 = 0.01863 MeV

1 MeV = 1000keV.

Thus, 0.01863 MeV = 0.01863*1000keV = 18.63 keV.

So, the energy released in the decay process = 18.63 keV.

7 0
3 years ago
Now consider the reaction when 45.0 g NaOH have been added. What amount of NaOH is this, and what amount of FeCl3 can be consume
gayaneshka [121]

The correct answer is that 1.125 mol of NaOH is available, and 60.75 g of FeCl₃ can be consumed.

The mass of NaOH is 45 g

The molar mass of NaOH = 40 g/mol

The moles of NaOH = mass / molar mass

= 45 / 40

= 1.125

Thus, 1.125 mol NaOH is available

3 NaOH + FeCl₃ ⇒ Fe (OH)₃ + 3NaCl

3 mol of NaOH react with 1 mol of FeCl₃

1.125 moles of NaOH will react with x moles of FeCl₃

x = 1.125 / 3

x = 0.375 mol

0.375 mol FeCl₃ can take part in reaction

The molar mass of FeCl₃ is 162 g/mol

The mass of FeCl₃ = moles × mass

= 0.375 × 162

= 60.75 g

Thus, the amount of FeCl₃, which can be consumed is 60.75 g

6 0
3 years ago
A sample of gas has an initial volume of 22.6 L at a pressure of 1.67 atm. If the sample is compressed to a volume of 10.0 L : ,
Sphinxa [80]

Answer:

3.74 atmospheres

Explanation:

If the temperature is constant, then the formula is

V*P = V1 * P1

V = 22.6 L

P = 1.67 atm

V1 = 10.0 L

P1 = ??

=============

22.6 * 1.67 = 10 * P1

37.742 = 10 * P1

37.742/10 = P1

P1 = 3.742

Note there are 3 sig digs in each given, so the answer should be

P1 = 3.74 atmospheres

8 0
3 years ago
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