Given the balanced equation representing a reaction:
1 answer:
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Answer:
Glycogen in an important storage polysaccharide found in animal tissues.
Explanation:
Full question:
Glycogen ________
A) forms the regulatory molecules known as enzymes
B) serves as a structural component of human cells
C) helps to protect vital organs from damage
D) is an important storage polysaccharide found in animal tissues
E) contains the genetic information found in cells
Glycogen is a complex polysaccharide of glucose founded in humans, animals, fungi and even bacteria. In humans, the glycogen is made and stored in liver cells. In the center on glycogen molecule, there is a single protein called Glycogenin. It is a center of a big flower made of glucose molecules (please refer to the scheme attached - Glycogenin is red and the blue lines are glucose chains). Glycogen is also stored in skeletal muscle, red and white blood cells, in glial brain cells and kidneys but in a smaller amounts. It can be found in the placenta in pregnant women where it serves as a nutrient storage for embryo. In an adult, the liver weighs 1,5 kg and glycogen weighs about 120g in such a liver. After a meal, the level of sugar is rising and the insulin is being secreted. Insulin is a tool by which sugar is being delivered to the cells, like a food delivery. During this period, glycogen is being synthesized in the liver out of glucose residues. When the meal is digested, the sugar level is back to normal. When more energy is needed, glycogen from the liver is broken down by glycogen phosphorylase and the new sugar is released into the bloodstream.
Consider the isomerization of butane with equilibrium constant is 2.5 .The system is originally at equilibrium with :
[butane]=1.0 M , [isobutane]=2.5 M
If 0.50 mol/L of butane is added to the original equilibrium mixture and the system shifts to a new equilibrium position, what is the equilibrium concentration of each gas?
Answer:
The equilibrium concentration of each gas:
[Butane] = 1.14 M
[isobutane] = 2.86 M
Explanation:
Butane ⇄ Isobutane
At equilibrium
1.0 M 2.5 M
After addition of 0.50 M of butane:
(1.0 + 0.50) M -
After equilibrium reestablishes:
(1.50-x)M (2.5+x)
The equilibrium expression will wriiten as:
x = 0.36 M
The equilibrium concentration of each gas:
[Butane]= (1.50-x) = 1.50 M - 0.36M = 1.14 M
[isobutane]= (2.5+x) = 2.50 M + 0.36 M = 2.86 M
Explanation:
The weak intermolecular forces which can arise either between nucleus and electrons or between electron-electron are known as dispersion forces. These forces are also known as London dispersion forces and these are temporary in nature.
Therefore, more is the surface area occupied by the carbon chain more will be the dispersion forces present in it. Hence, less is the surface area occupied by a molecule less will be the dispersion forces present in it.
Hence, the given molecules are organized from largest to smallest dispersion forces as follows.
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