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2 years ago

James made $85.00 in 2 weeks mowing yards. He spent 20% of that buying new tools. How much did he spend on tools? *

Mathematics

2 answers:

Lelu [443]2 years ago

8 0

Answer:

C. $17

Step-by-step explanation:

85 x (1/5) = 17

Kruka [31]2 years ago

5 0

Answer: c 17

Step-by-step explanation:

Easy

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zhuklara [117]

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The answer is d

Step-by-step explanation:

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3 years ago

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a baseball team has a tub. the tub has a width of 150 and a length of 150 plus the height of 80. What is the capacity of the tub

Mrrafil [7]

Answer:

1800 liters

Step-by-step explanation:

150*150*80=1800000 cubic cm

1800000/1000= 1800 liters

Might seem like a lot but really isn't.

6 0

2 years ago

If (4 to the 4 power) to the x power = 4 to the 32 power, what is the value of x?

gizmo_the_mogwai [7]

(4 to the 4 power) to the x power = 4 to the 32 power

(4^4)^x = 4^32

4^4x = 4^32

4x = 32

x = 8

Answer

x = 8

8 0

3 years ago

FURTHER MATHEMATICS Use determinants to solve the systems of equation:

maw [93]

Answer:

Step-by-step explanation:

$\left\{\begin{array}{ccc}2x+1y+2z&=&13\\1x+1y-2z&=&8\\1x+2y+1z&=&11\\\end{array}\right.\\\\\\\Delta=\left| \begin{array}{ccc}2&1&2\\1&1&-2\\1&2&1\end{array}\right| =2*\left| \begin{array}{ccc}1&\frac{1}{2}&1\\1&1&-2\\1&2&1\end{array}\right| =2*\left| \begin{array}{ccc}1&\frac{1}{2}&1\\0&\frac{1}{2}&-3\\0&1&3\end{array}\right| =2*(\frac{3}{2}+3)=9\\\\$

$\Delta_1=\left| \begin{array}{ccc}13&1&2\\8&1&-2\\11&2&1\end{array}\right| =2*\left| \begin{array}{ccc}13&1&2\\8&1&-2\\\frac{11}{2}& 1&\frac{1}{2}\end{array}\right| =2*\left| \begin{array}{ccc}13&1&2\\-5&0&-4\\\frac{-5}{2}& 0&\frac{5}{2}\end{array}\right| \\\\=2*(-1)*(\frac{-25}{2}-\frac{20}{2}) =45\\$

$\Delta_2=\left| \begin{array}{ccc}2&13&2\\1&8&-2\\1&11&1\end{array}\right| \\\\\\=\left| \begin{array}{ccc}3&21&0\\3&30&0\\1&11&1\end{array}\right| \\\\\\=1*(90-63) =27\\$

$\Delta_3=\left| \begin{array}{ccc}2&1&13\\1&1&8\\1&2&11\end{array}\right| \\\\\\=\left| \begin{array}{ccc}0&-1&-3\\0&-1&-3\\1&2&11\end{array}\right| \\\\\\=0\\$

$\left\{\begin{array}{ccc}x=\dfrac{\Delta_1}{\Delta}=\dfrac{45}{9}=5\\\\y=\dfrac{\Delta_2}{\Delta}=\dfrac{27}{9}=3\\\\z=\dfrac{\Delta_3}{\Delta}=\dfrac{0}{9}=0\\\end{array}\right.$