Answer:
Compound A: Benzoyl chloride
Compound B: Benzaldehyde - (tBuO)₃Al complex
Compound C: Benzaldehyde
Compound D: Benzyl alcohol
Explanation:
The lithium tri-tert-butoxyaluminum hydride that the first student used is a milder reagent than LAH and will stop reacting at the aldehyde.
The LAH that the second student used is much more reactive and will continue to reduce the benzoic acid as far as possible, going all the way to the alcohol.
See the attachment for the reaction steps.
Answer:
8.9x10¹⁷ atoms of Al are present
Explanation:
To find the number of atoms from the mass of an atom we must convert, as first, the mass to moles using the molar mass of the atom (26.98g/mol For Aluminium).
Then, we must convert the moles to atoms knowing that 1mol = 6.022x10²³ atoms.
<em>Moles Aluminium:</em>
4.0x10⁻⁵g * (1mol / 26.98g) = 1.483x10⁻⁶ moles Al
<em>atoms:</em>
1.483x10⁻⁶ moles Al * (6.022x10²³ atoms / mol) =
<h3>8.9x10¹⁷ atoms of Al are present</h3>
Pcl3 mols= 25/137.2mol
cl mols formd by pcl3= 25*1.5/137.2
cl mass= 25*1.5*71/137.2
It’s not a or b or c or d it’s the only one
Answer:
They form crystals,They're good insulators
Explanation: