Addition of sodium carbonate is a way to soften water by removing calcium ions
<h3>How calcium ions are removed?</h3>
Water can be softened by the addition of lime to precipitate the calcium as carbonate. Sodium carbonate is also added to remove the remaining calcium salts and to make the water soft.
So we can conclude that addition of lime or sodium carbonate is a way to soften water by removing calcium ions.
Learn more about calcium here: brainly.com/question/26636816
S + O2 → SO2
Moles of S:
11/32.06 = 0.3431 mol
Moles of O2:
44/15.999 = 2.75 mol
Sulfur will be the limiting reagent.
Oxygen will be the excess reagent
2.75 - 0.3431 = 2.4071 mols of oxygen leftover
2.4071 * 15.999 = 38.511
38.511 grams of oxygen will be leftover
Q = m . C . Δ T
q : Heat absorbed
m : mass of the sample
C : The specific heat of the substance.
Δ T : The change in temperature (Final T - initial T)
So:
q = 15.5 x 4.18 x (50 - 25) = 1619.75 J
Answer:
a) 10.0 mm
b) 8.7 x 10¹³ times
Explanation:
Atom diameter = 1.06 x 10⁻¹⁰ m ________________ 100%
Nucleus diameter = 2.40 x 10⁻¹⁵ m ______________ x
x = 2.26 x 10⁻³ %
The nucleus diameter is equivalent to 2.26 x 10⁻³ % of the total atom size.
a) The Empire State Building model:
1 ft = 304.8 mm
1454 ft = 443179.2 mm
443179.2 mm______ 100%
y ______ 2.26 x 10⁻³ %
y = 10.0 mm
In this model, the diameter of the nucleus would be 10.0 mm.
b) Sphere volume: V =(4 · π · r³
)/3
V atom = (4 . π .( 0.53x10⁻¹⁰)³ )/3
V atom = 6.2 x 10⁻³¹ m³
V nucleus = (4 . π .( 1.2x10⁻¹⁵)³ )/3
V nucleus = 7.2 x 10⁻⁴⁵ m³
V atom / V nucleus = 6.2 x 10⁻³¹ m³ / 7.2 x 10⁻⁴⁵ m³
V atom / V nucleus = 8.7 x 10¹³
The atom is times 8.7 x 10¹³ larger in volume than its nucleus.
