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Liula [17]
3 years ago
12

A square poster has a side length of 26 in. Drawn on the poster are four identical triangles. Each triangle has a base of 8 in.

and a height of 8 in. Children play a game in which they each wear a blindfold and throw a dart at the poster. A player whose dart lands inside a triangle wins a prize.
Assuming that a player's dart will always land on the poster, what is the probability of the dart landing in a triangle?

Enter your answer, as a decimal rounded to the nearest hundredth, in the box.

P(a point on a triangle) =
Mathematics
1 answer:
dybincka [34]3 years ago
8 0
Probbility=\frac{desired}{total}
P_{triangle}=\frac{Area_{triangle}}{Area_{total}}
P_{triangle}=\frac{4\times\frac{b \times h}{2}}{s^{2}}
P_{triangle}=\frac{4\times\frac{8 \times 8}{2}}{26^{2}}
P_{triangle}=\frac{4\times\frac{64}{2}}{676}
P_{triangle}=\frac{128}{676}
P_{triangle}=0.189349112
P_{triangle=0.19
P_{triangle}\approx19\%
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The green triangle is a dilation of the red triangle with a scale factor of s=1/3 and the center of dilation is at the point (4,
klasskru [66]

Given:

The scale factor is s=\dfrac{1}{3} and the center of dilation is at the point (4,2).

Red is original figure and green is dilated figure.

To find:

The coordinates of point C' and point A.

Solution:

Rule of dilation: If a figure is dilated with a scale factor k and the center of dilation is at the point (a,b), then

(x,y)\to (k(x-a)+a,k(y-b)+b)

According to the given information, the scale factor is \dfrac{1}{3} and the center of dilation is at (4,2).

(x,y)\to (\dfrac{1}{3}(x-4)+4,\dfrac{1}{3}(y-2)+2)            ...(i)

Let us assume the vertices of red triangle are A(m,n), B(10,14) and C(-2,11).

Using (i), we get

C(-2,11)\to C'(\dfrac{1}{3}(-2-4)+4,\dfrac{1}{3}(11-2)+2)

C(-2,11)\to C'(\dfrac{1}{3}(-6)+4,\dfrac{1}{3}(9)+2)

C(-2,11)\to C'(-2+4,3+2)

C(-2,11)\to C'(2,5)

Therefore, the coordinates of Point C' are C'(2,5).

We assumed that point A is A(m,n).

Using (i), we get

A(m,n)\to A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)

From the given figure it is clear that the image of point A is (8,4).

A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)=A'(8,4)

On comparing both sides, we get

\dfrac{1}{3}(m-4)+4=8

\dfrac{1}{3}(m-4)=8-4

(m-4)=3(4)

m=12+4

m=16

And,

\dfrac{1}{3}(n-2)+2=4

\dfrac{1}{3}(n-2)=4-2

(n-2)=3(2)

n=6+2

n=8

Therefore, the coordinates of point A are (16,8).

5 0
3 years ago
What type of triangle has 3 sides that are the same length?
koban [17]
An equilateral triangle.
3 0
3 years ago
Read 2 more answers
What is the answer to -1 = -5/2 (-2) + 4
Klio2033 [76]

Answer:

it's false

the true is -1/2

Step-by-step explanation:

-5/2-2+4=-1/2

7 0
3 years ago
The figures are similar. Find x.
kipiarov [429]
6/9=x/21
x=21*6/9
=126/9
x=14
6 0
3 years ago
I have 3 more help please
ira [324]
Ok -13*-8 is 104.
-8*18q is 144q.
Combine an you get:
144q+104
3 0
3 years ago
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