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balu736 [363]
3 years ago
9

DESPERATE!! WILL GIVE BARINLIST AND THANKS

Physics
2 answers:
Finger [1]3 years ago
3 0

Answer:

it grabs unto soil and keeps it clamped together it prevents this makes the soil harder to wash away

Murljashka [212]3 years ago
3 0

Answer:

When the leftovers are left in the autumn, they have two purposes:

- Preventing erosion; the roots remain in the ground, so they hold it tightly till the next planting of the crops.

- Fertilizing the soil with natural material; the roots will not rot quickly in the colder period of the year, but will start rotting much faster in the spring, thus they will enrich the soil.

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Can power be negative in physics? I am doing a lab in which I run down the stairs as quickly as possible. They are 5.4m tall and
RUDIKE [14]

Answer:

Yes.

Explanation:

A negative power would just represent a loss of power. So in your case it lost -1252.16 W

8 0
3 years ago
For each statement in the rows, select the most suitable option (words) in the columns. One selection for each row.
Korvikt [17]

Answer:

the answer is most likely likely to be 2

5 0
3 years ago
why it's impossible for baseball players to make sharp turns when moving form base to base? explain using Newton 1st law "object
AVprozaik [17]

Answer:

An object that is moving wants to stay moving in a straight line. It takes an outside force acting upon it to change its direction or cause an acceleration.

Explanation:

7 0
3 years ago
Help yet again :) A hockey player is skating on the ice at 15km/h. He shoots the puck at 138 km/h according to a radar gun on th
IceJOKER [234]

Answer:

speed of puck acc. to the radar gun = 138 km/h

speed of player = 15 km/h

since the player is in motion when he shoots, the speed of the puck will be the sum of the speed of the player and the speed at which he shot. so,

speed of puck = speed of player + speed of puck acc. to player

138 = 15 + speed of puck acc. to player

speed of puck acc. to player = 138 -15

speed of puck acc. to player = 123 km/h

Brainly this answer if you think it deserves it

7 0
3 years ago
A boat race runs along a triangular course marked by buoys A, B, and C. The race starts with the boats headed west for 3700 mete
ale4655 [162]

Answer:

The  last two bearings are

49.50° and 104.02°

Explanation:

Applying the Law of cosine (refer to the figure attached):

we have

x² = y² + z² - 2yz × cosX

here,

x, y and z represents the lengths of sides opposite to the angels X,Y and Z.

Thus we have,

cos X=\frac{x^2-y^2-z^2}{-2yz}

or

cos X=\frac{y^2 + z^2-x^2}{2yz}

substituting the values in the equation we get,

cos X=\frac{2900^2 + 3700^2-1700^2}{2\times 2900\times 3700}

or

cos X=0.8951

or

X = 26.47°

similarly,

cos Y=\frac{1700^2 + 3700^2-2900^2}{2\times 1700\times 3700}

or

cos Y=0.649

or

Y = 49.50°

Consequently, the angel Z = 180° - 49.50 - 26.47 = 104.02°

The bearing of 2 last legs of race are angels Y and Z.

7 0
3 years ago
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