Where on a roller coaster are there equal amounts of potential energy and kinetic energy?

Two long, straight wires are separated by a distance of 9.15 cm . One wire carries a current of 2.79 A , the other carries a cur

Dafna1 [17]

Answer:

The force is the same

Explanation:

The force per meter exerted between two wires carrying a current is given by the formula

$\frac{F}{L}=\frac{\mu_0 I_1 I_2}{2\pi r}$

where

$\mu_0$ is the vacuum permeability

$I_1$ is the current in the 1st wire

$I_2$ is the current in the 2nd wire

r is the separation between the wires

In this problem

$I_1=2.79 A\\I_2=4.36 A\\r = 9.15 cm = 0.0915 m$

Substituting, we find the force per unit length on the two wires:

$\frac{F}{L}=\frac{(4\pi \cdot 10^{-7})(2.79)(4.36)}{2\pi (0.0915)}=2.66\cdot 10^{-5}N$

However, the formula is the same for the two wires: this means that the force per meter exerted on the two wires is the same.

The same conclusion comes out from Newton's third law of motion, which states that when an object A exerts a force on an object B, then object B exerts an equal and opposite force on object A (action-reaction). If we apply the law to this situation, we see that the force exerted by wire 1 on wire 2 is the same as the force exerted by wire 2 on wire 1 (however the direction is opposite).

3 0

3 years ago

The drag force that resists the motion of a car traveling at 80 km h^- 1 is 300 N.

kobusy [5.1K]

The power require to keep the car traveling is 6,666 W.

The power of the engine at the given efficiency is 3,999.6 W.

<h3>What is Instantaneous power?</h3>

This the product of force and velocity of the given object.

The power require to keep the car traveling is calculated as follows;

P = Fv

$P = 300\ N \ \times \ \frac{80 \ kmh^{-1}}{3.6 \ km h^{-1}/m/s} \\\\
P = 300 \ N \times 22.22 \ m/s\\\\
P = 6,666 \ W$

The power of the engine at the given efficiency is calculated as follows;

$E = \frac{P_{out}}{P _{in}} \times 100\%\\\\
60\% = \frac{P_{out}}{6,666} \times 100\%\\\\
0.6 = \frac{P_{out}}{6,666} \\\\
P_{out} = 3,999.6 \ W$

Learn more about efficiency here: brainly.com/question/15418098

8 0

2 years ago

The length and mass of the arm are Larm = X1 = 50 cm and Marm = 0.3 kg, X2 = 15 cm, and the mass of the object is MObject = 0.25

max2010maxim [7]

Answer: 0.5N

Explanation: if the system is at equilibrium, sum of the torque will be equal to zero.

But if they are not in equilibrium.

U will find the difference in the two torque

find the attached file for solution

3 0

2 years ago

Which properties define light as a wave?

Naddik [55]

Properties that define the light is a wave are

1. Speed : speed of light is 300,000 Km /s, It is most fundamenta property of light to define light is a wave

2. Reflection: Light particles or photons reflect off the particles or masses are continue to travel at the same speed.

3. colour

6 0

3 years ago

Two identically built microscopes are being used to characterize sub-micron features with two different laser sources. The first

Agata [3.3K]

Answer:

$r_2\approx430\ nm$

Explanation:

Given:

wavelength used by the first microscope, $\lambda_1=632\times 10^{-9}\ m$

resolving power of the first microscope, $r_1=500\times 10^{-9}\ m$

wavelength used by the second microscope, $\lambda_2=543\times 10^{-9}\ m$

For the microscopes the resolving power is given as:

$r=1.22\times \frac{\lambda}{a}$

where:

$\lambda =$ wavelength of the laser source used

$a=$ numerical aperture of the microscope

$r=$ smallest feature that can be distinguished using the optical device

For the first microscope:

$r_1=1.22\times \frac{\lambda_1}{a_1}$

$500\times 10^{-9}=1.22\times\frac{632\times 10^{-9}}{a_1}$

$a_1=1.54208$

Since both the optical device are identically built we will have:

$a_2=a_1=1.54208$

Now for the second optical device:

$r_2=1.22\times \frac{\lambda_2}{a_2}$

$r_2=1.22\times \frac{543\times 10^{-9}}{1.54208}$

$r_2\approx430\ nm$

3 0

3 years ago