Each number goes up by multiplying by 2.
For example, the 1 got to 2 by 1 x 2 and 2 got to 4 by 2 x 2 = 4.
You would continue this pattern by doing 8 x 2 = 16 for the first blank.
16 x 2 = 32 for the second blank
32 x 2 = 64 for the third blank
64 x 2 = 128 to check your work.
So the answer would be: 1, 2, 4, 8, 16, 32, 64, 128
If <span>I
understand the question correct, the hockey season ticket holder paid
$72.48 for all of the tickets at once, and then $6.00 for each game
thereafter. The second person pays $18.08 for a ticket per game.
So then let g = the number of games. The problem can be written as a system of equations:
Person 1 = 72.48 + 6g
Person 2 = 18.08g
We are looking for when the number of games for both are the same. To do
this, just set them equal to each other and solve for g.
72.48 + 6g = 18.08g
Subtract 6g:
72.48 = 12.08g
Divide by 12.08:
g = 6
So after 6 games, the two would have paid the same price.
</span>
A1=12
d=a2-a1→d=2-7=-5
a33=a1+32d→a33=12+32(-5)→a33=12-160=-148
Just need to convert the mass of moon in terms of 10^24. So shift over 2 decimal places.
5.97 x 10^24 + 0.0734 x 10^24 = 6.04 x10^24