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DedPeter [7]
3 years ago
11

:”)

Physics
1 answer:
ludmilkaskok [199]3 years ago
3 0

Answer:

Explanation:

1)  average velocity is

v = (21 + 39)/2 = 30m m/s

d = vt 30(4.1) = 123 = 120 m

2)  d = ½gt²

d = ½(9.8)(4.1²)

d = 82.369 = 82 m

when rounding to the two significant digits of the question numerals.

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Por favor, necesito ayuda urgente 4. vectores perpendiculares de 25 y 40 unidades cada uno. Hallar gráfica y numericamente el ve
Darina [25.2K]

Answer:

4)  R = 47.17 units , 5)  R= 10,29 unidades, 6)   R= 2994,4 km ,    θ = -33,7

Explanation:

Este es un ejercicio de adición de vectores

4) como los vectores son perpendiculares.

Para encontrar la resultante podemos usar el teorema de pitoras

        R =  √ a² + b²

        R = √√ ( 25² + 40²)

        R =  47,17 unidades

5)  Este caso como el angulo es diferente de 90 debemos usar la relación de pitoras completa

        R² =  a² + b² + 2 a b cos θ

donde el angulo es entre los vectores a y b

        R² = 12² + 16² – 2 12 16 cos 40

        R²= 400 – 294,16

       R= 10,29 unidades

6) En este caso los dos desplazamientos son perpendiculares, por lo cual Usamos el teorema de Pitágoras

          R = √ (2400² + 1600²)

          R= 2994,4 km

para el angulo de este desplazamiento usamos trigonometría

           tan θ = y/x

           θ = tan⁻¹ y/x

           θ = tan⁻¹ 1600/(-2400)

           θ = -33,7  

TRASLATE

This is a vector addition exercise

4) as the vectors are perpendicular.

To find the result we can use the Poreor theorem

        R = √ a² + b²

        R = √ (25² + 40²)

        R = 47.17 units

5) This case, as the angle is different from 90, we must use the complete ratio of the pitoras

        R² = a² + b² + 2 a b cos θ

where the angle is between vectors a and b

        R² = 12² + 16² - 2 12 16 cos 40

         R² = 400 - 294.16

       R = 10.29 units

6) In this case the two displacements are perpendicular, which is why we use the Pythagorean theorem

          R = √ (2400² + 1600²)

          R = 2,994.4 km

for the angle of this displacement we use trigonometry

           tan θ = y / x

           θ = tan⁻¹ y / x

           θ = tan⁻¹ 1600 / (- 2400)

           θ = -33.7

3 0
3 years ago
Scientists use models to
xxTIMURxx [149]
D Is Thw Correct answer
3 0
3 years ago
The radius of the earth's very nearly circular orbit around the sun is 1.5 1011 m. find the magnitude of the earth's velocity, a
kotykmax [81]
The radius of Earth's circular trajectory is
R=1.5*10^{11} m
The time for the Earth to travel around the Sun is
t=365(days)*24(hours)*3600(seconds) =3.1536*10^7 (s)
Thus the velocity is velocity
v=2\pi R/t =2\pi *1.5*10^{11}/(3.1536*10^{7})=2.99*10^4 (m/s)
From this we can deduce the centripetal acceleration
a=v^2/R =(2.99*10^4)^2/(1.5*10^{11}) =5.96*10^{-3}  (m/s^2)
Angular velocity is
\omega =v/R =(2.99*10^4)/(1.5*10^{11})=2*10^{-7} (rad/s)

5 0
4 years ago
how might testing small-scale building models or their components be helpful in testing improvements and changes to the building
azamat

Answer: & Explanation:

small scaled building models are very rare to make/build nowadays.

due to advance technology it is more wiser and more convenient to use 3d programs like revit in creating building model to scale.

so It is always a good idea to make models of your ideas, before deciding on the final design.

This will help you determine whether your idea is going to work or needs modifying. A model allows you to test your solution quickly and cheaply.

Reworking a massive building takes years, millions of pounds, and meticulous planning and project management.

4 0
4 years ago
Is F=mxa expressed in equation in newtons second law of motion?
kow [346]
Yes. That equation is exactly how we write Newton's second law nowadays. Note that the 'x' just means 'times'. It's not another variable. The equation could be written as simply. F = m a .
6 0
4 years ago
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