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4 years ago

What is the biggest current disadvantage to using gas hydrates as a form of energy?

2 answers:

6 0

When gas hydrates are brought to the surface, they evaporate quickly. This would be the biggest, current disadvantage to using gas hydrates as a form of energy.

Rama09 [41]4 years ago

6 0

ANSWER)
they evaporate quickly when brought to the surface :-()

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A liquid with a density of 900kg/m 3 is stored in a pressurized, closed storage tank. The tank is cylindrical with a 10m diamete

Orlov [11]

Answer:

18.62 m/s

Explanation:

Given that:

A liquid with a density of 900 kg/m 3 is stored in a pressurized, closed storage tank.

Diameter of the tank = 10 m

The absolute pressure in the tank above the liquid is 200 kPa = 200, 000 Pa

At pressure of 200 kPa ; the final velocity = 0

Atmospheric pressure at 5cm = 101325 Pa

We are to calculate the initial velocity of a fluid jet when a 5cm diameter orifice is opened at point A?

By using Bernoulli's theorem between the shaded portion in the diagram;

we have:

$Pa \ + \ \frac{1}{2} \ \delta \ v^2_1 \ + \ \delta gy_1 = P + \delta gy_2$

$\frac{1}{2} \ \delta \ v^2_1 \ = P + \delta gy_2 - \ \delta gy_1 - Pa$

$\frac{1}{2} \ \delta \ v^2_1 \ = \delta g(y_2 -y_1 )+ ( P - Pa )$

$v_1 \ = \sqrt{ \frac {2 \ \delta g(y_2 -y_1 )+ 2 ( P - Pa )}{\delta}}$

where;

Pa = atmospheric pressure = 101325 Pa

$\delta$ = density of liquid = 900 kg/m³

$v_1$ = initial velocity = ???

g = 9.8 m/s²

$y_1$ = height of the hole from the buttom

$y_2$ = height of the liquid surface from the button

$v_1 \ = \sqrt{ \frac {2*900*9.8(7 - 0.5 )+ 2 ( 200,000 - 101325 )}{900}}$

$v_1 = 18.62 \ m/s$

Thus, the initial velocity of the fluid jet = 18.62 m/s

3 0

3 years ago

In the two-slit experiment, monochromatic light of wavelength 600 nm passes through a 19) pair of slits separated by 2.20 x 10-5

kumpel [21]

Explanation:

It is given that,

Wavelength of monochromatic light, $\lambda=600\ nm=6\times 10^{-7}\ m$

Slits separation, $d=2.2\times 10^{-5}\ m$

(a) We need to find the angle corresponding to the first bright fringe. For bright fringe the equation is given as :

$d\ sin\theta=n\lambda$ , n = 1

$\theta=sin^{-1}(\dfrac{\lambda}{d})$

$\theta=sin^{-1}(\dfrac{6\times 10^{-7}}{2.2\times 10^{-5}})$

$\theta=1.56^{\circ}$

(b) We need to find the angle corresponding to the second dark fringe, n = 1

So, $d\ sin\theta=(n+\dfrac{1}{2})\lambda$

$sin\theta=\dfrac{3\lambda}{2d}$

$\theta=sin^{-1}(\dfrac{3\lambda}{2d})$

$\theta=sin^{-1}(\dfrac{3\times 6\times 10^{-7}}{2\times 2.2\times 10^{-5}})$

$\theta=2.34^{\circ}$

Hence, this is the required solution.

4 0

4 years ago

Which of these is an example of climate? A. a weather forecast B. last month's total rainfall C. the current temperature D. an a

Monica [59]

Answer:

The answer to your question is D An annual weather pattern

Explanation:

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3 years ago

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Anettt [7]

Answer:

Organisms and their environment

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3 years ago

A machine is applying a torque to rotationally accelerate a metal disk during a manufacturing process. An engineer is using a gr

Viefleur [7K]

Explanation:

Question 9 A machine is applying a torque to rotationally accelerate a metal disk during a manufacturing process. An engineer is using a graph of torque as a function of time to determine how much the disk's angular speed increases during the process The graph of torque as a function of time starts at an initial torque value and is a straight line with positive slope. What aspect of the graph and possibly other quantities must be used to calculate how much the disk's angular speed increases during the process? The slope of the graph multiplied by the disk's radius will equal the change in angular speed The area under the graph multiplied by the disk's radius will equal the change in angular speed. The slope of the graph divided by the disk's rotational inertia will equal the change in angular speed. The area under the graph divided by the disk's rotational inertia will equal the change in angular speed. The area under the graph multiplied by the disk's rotational inertia will equal the change in angular speed E

8 0

3 years ago

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