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MariettaO [177]
4 years ago
15

Assign the oxidation state for all the atoms:As2O3Show work

Chemistry
1 answer:
Sonja [21]4 years ago
3 0

<u>Answer:</u> Oxidation state of Arsenic in the given compound is +3 and that of oxygen is -2.

<u>Explanation:</u>

We are given a compound having formula As_2O_3 and we need to find the oxidation state of all the atoms in this compound. There are 2 different atoms present in this : Arsenic and Oxygen

Oxidation state is the number which is assigned to an element in a compound which represents the number of electrons lost or gained by an atom in a compound.

Oxidation state of oxygen as -2 which is same always. Now, to calculate the oxidation state of Arsenic, we take the oxidation state of it be 'x'

As, there are two arsenic atoms and three oxygen atoms, then:

\Rightarrow 2(x)+3(-2)=0\\\Rightarrow 2x-6=0\\\Rightarrow x=+3

Hence, oxidation state of Arsenic in the given compound is +3 and that of oxygen is -2.

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F a balloon containing 1000 L of gas 50 Celsius and 101.3kpa rises to an altitude where pressure is 27.5 kpa amd the temperature
inna [77]

Answer:

V₂ =  3227.46 L

Explanation:

Given data:

Initial volume of gas = 1000 L

Initial temperature = 50°C  (50 +273 = 323 K)

Initial pressure = 101.3 KPa

Final pressure = 27.5 KPa

Final temperature = 10°C  (10 +273 = 283 K)

Final volume = ?

Solution:

According to general gas equation:

P₁V₁/T₁ = P₂V₂/T₂

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Now we will put the values in formula.

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 101.3 KPa × 1000 L × 283 K / 323 K × 27.5 KPa

V₂ = 28667900 KPa .L. K /   8882.5 K.KPa

V₂ =  3227.46 L

7 0
3 years ago
During photosynthesis, carbon dioxide, water, and energy react to form glucose and oxygen. Which line would be longer on the ene
timama [110]

Answer:

The vertical line indicating bonds breaking

Explanation:

3 0
2 years ago
How many sulfur atoms are in 3.7 mol of SO2?<br><br> × 10 S atoms
Allisa [31]

Answer: 22.3 *10^23 S atoms

Explanation:

8 0
3 years ago
Element X had a mass of 300g and a 1/2 life of 10 years. how many grams will remain after 40 years?
kiruha [24]
<h3>Answer:</h3>

18.75 grams

<h3>Explanation:</h3>
  • Half-life refers to the time taken by a radioactive material to decay by half of the original mass.
  • In this case, the half-life of element X is 10 years, which means it takes 10 years for a given mass of the element to decay by half of its original mass.
  • To calculate the amount that remained after decay we use;

Remaining mass = Original mass × (1/2)^n, where n is the number of half-lives

Number of half-lives = Time for the decay ÷ Half-life

                                 = 40 years ÷ 10 years

                                  = 4

Therefore;

Remaining mass = 300 g × (1/2)⁴

                            = 300 g × 1/16

                             = 18.75 g

Hence, a mass of 300 g of an element X decays to 18.75 g after 40 years.

3 0
4 years ago
You heat 51 grams of magnesium over a Bunsen burner for several minutes until it reacts with oxygen in the air. Then you weigh t
garik1379 [7]

Answer:

    The mass was there all along, it was just in the air. The weight of the oxygen from the air is not weighed in the beginning, only at the end as part of the product, making it seem like there is a total mass change.

8 0
3 years ago
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