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3 years ago

6.02 x 1023 Significant figures

Chemistry

1 answer:

Bond [772]3 years ago

3 0

Answer:

It depends on the number of significant figures you are changing to

Explanation:

6.02×1023=6158.46

1 sig fig = 6000

2 sig fig = 6200

3 sig fig = 6160

4 sig fig = 6158

5 sig fig = 6158.5

6 sig fig = 6158.46

When solving significant figures you have to consider the number after each number like in the case of changing to two sig fig the number following one is five and when the number is up to or greater than five you add a value of one to the number before it. But in a case where the number is less than five you just leave it like that like in the case of changing to one sig fig

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A chemist prepares a solution of copper(II) fluoride by measuring out of copper(II) fluoride into a volumetric flask and filling

Simora [160]

The question is incomplete, here is the complete question.

A chemist prepares a solution of copper(II) fluoride by measuring out 0.0498 g of copper(II) fluoride into a 100.0mL volumetric flask and filling the flask to the mark with water.

Calculate the concentration in mol/L of the chemist's copper(II) fluoride solution. Round your answer to 3 significant digits.

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Explanation:

To calculate the molarity of solute, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Given mass of copper (II) fluoride = 0.0498 g

Molar mass of copper (II) fluoride = 101.54 g/mol

Volume of solution = 100.0 mL

Putting values in above equation, we get:

$\text{Molarity of copper (II) fluoride)=\frac{0.0498\times 1000}{101.54\times 100.0}\\\\\text{Molarity of copper (II) fluoride}=4.90\times 10^{-3}mol/L$

Hence, the concentration of copper fluoride in the solution is $4.90\times 10^{-3}mol/L$

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Answer:

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