Which one is a physical change?
2 answers:
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Answer:
The answer to the questions are as follows
Reaction B is 4426.28 times faster than reaction A
(b) Reaction B is faster.
Explanation:
To solve the question we are meant to compare both reactions to see which one is faster
The values of the given activation energies are as follows
For A
Ea = 95.00 kJ mol–1 (22.71 kcal mol–1) and
for B
Ea = 74.20 kJ mol–1 (17.73 kcal mol–1)
T is the same for both reactions and is equal to 298 k
Concentration of both reaction = 1M
The Arrhenius Law is given by
k =
Where
k = rate constant
Ea = activation energy
R = universal gas constant
T = temperature (Kelvin )
A = Arrhenius factor
Therefore
For reaction A, the rate constant k₁ is given by k₁ =
And for B the rate constant k₂ is given by k₂ =
k₁ = A×2.225×10⁻¹⁷
k₂ = A×9.850×10⁻¹⁴
As seen from the above Reaction B is faster than reaction A by (A×9.850×10⁻¹⁴)/(A×2.225×10⁻¹⁷) or 4426.28 times
<em>The mass of a gold bar = 1.424 x 10⁴ gram</em>
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<h3><em>Further Explanation</em></h3>Density is a quantity derived from the mass and volume
density is the ratio of mass per unit volume
With the same mass, the volume of objects that have a high density will be smaller than type
The unit of density can be expressed in g / cm3 or kg / m3
Density formula:
ρ = density
m = mass
v = volume
A common example is the water density of 1 gr / cm3
The mass itself is often equated with weight, even though it is different. Mass is the amount of matter in the matter while weight is related to the gravitational force
<em>Known variable</em>
volume gold bar 7.379 × 10⁻⁴ m³
a density of 19.3 g/cm³
<em>Asked</em>
the mass of a gold bar
<em>Answer</em>
volume is known to be 7.379 × 10⁻⁴ m³, then we change it first to units of cm³ adjusting to units of density
7.379 × 10⁻⁴ m³ = 7.379 × 10² cm³
then:
mass = volume x density
mass = 7.379 × 10² cm³ x 19.3 g/cm³
mass = 1.424 x 10⁴ gram
<h3><em>Learn more </em></h3>density acetone
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Keywords: density, mass, volume, a gold bar
Answer:
Reagents: 1) 2)
,
Mechanism: Hydroboration
Explanation:
In this case, we have a <u>hydration of alkene</u>s reaction. But, in this example, we have an <u>anti-Markovnikov reaction</u>. In other words, the "OH" is added in the least substituted carbon. Therefore we have to choose an anti-Markovnikov reaction: <u>"hydroboration"</u>.
The <u>first step</u> of this reaction is the addition of borane () to the double bond. Then in the <u>second step</u>, we have the deprotonation of the hydrogen peroxide, to obtain the peroxide anion. In the <u>third step</u>, the peroxide anion attacks the molecule produced in the first step to produce a complex compound in which we have a bond "
". In <u>step number 4</u> we have the migration of the C-B bond to oxygen. Then in <u>step number 5</u>, we have the attack of
on the
to produce an alkoxide. Finally, the water molecule produce in step 2 will <u>protonate</u> the molecule to produce the alcohol.
See figure 1
I hope it helps!
