All categories

3 years ago

Through which type of media do mechanical waves, such as sound, move the fastest?

1 answer:

monitta3 years ago

8 0

Mechanical waves travel the fastest in solids and liquids because the molecules are more closely packed together than gases, so energy is transferred from one particle to another particle faster.

You might be interested in

Which statement best compares the acceleration of two objects in free fall?

Anastasy [175]

Answer

4.The objects have the same acceleration

Explanation

Acceleration due to gravity is the acceleration acquired by an object when falling freely.

Under normal conditions, different objects has different accelerations depending on their mass and surface area. This is brought about by the air resistance they experience as they fall.

The case is difference when they the experiment is carried out in a controlled condition. That is in vacuum. I this case the acceleration of the objects is the same.

6 0

3 years ago

Read 2 more answers

Unless indicated otherwise, assume the speed of sound in air to be v = 344 m/s. You have a stopped pipe of adjustable length clo

faltersainse [42]

Answer:

Length of pipe $= 0.057$ meter

Explanation:

Speed of a transverse wave on a string

$v = \sqrt{\frac{F}{\mu} }$

where F is the tension in string and $\mu$ is the mass per unit length

Thus,

$\mu = \frac{m}{L}$

Substituting the given values we get -

$\mu = \frac{7.25 * 10^{-3}}{0.62}\\mu = 0.0117 \frac{Kg}{m}$

Speed of a transverse wave on a string

$v = \sqrt{\frac{4510}{0.0117} } \\v = 620.86 \frac{m}{s}$

For third harmonic wave , frequency is equal to

$f = \frac{nv}{2L}$

Substituting the given values, we get -

$f = \frac{3 * 620.86}{2 * 0.62} \\f = 1502.08$

Length of pipe

$L = \frac{nv}{4 f}$

Substituting the given values we get

$n = 1$ for first harmonic wave

$L = \frac{344* 1}{4*1502.08} \\L = 0.057$

Length of pipe $= 0.057$ meter

5 0

4 years ago

Water flows over a fall that is 125.0 m high. If the potential energy of the water is all converted to thermal energy, calculate

Pavel [41]

Answer:

ΔT = 0.29°C

Explanation:

Using the law of conservation of energy:

$Potential\ Energy = Thermal\ Energy\\mgh = mC\Delta T\\gh = C\ \Delta T\\\\\Delta T = \frac{gh}{C}$

where,

ΔT = Temperature difference between the water at the top and the bottom of the fall = ?

g = acceleration due to gravity = 9.81 m/s²

h = height of fall = 125 m

C = specific heat capacity of water = 4200 J/kg

Therefore,

$\Delta T = \frac{(9.81\ m/s^2)(125\ m)}{4200\ J/kg^oC}\\\\$

ΔT = 0.29°C

8 0

3 years ago

If a rainstorm drops 5 cm of rain over an area of 13 km2 in the period of 3 hours, what is the momentum (in kg · m/s) of the rai

stiks02 [169]

To solve the problem it is necessary to apply the concepts related to Conservation of linear Moment.

The expression that defines the linear momentum is expressed as

P=mv

Where,

m=mass

v= velocity

According to our data we have to

v=10m/s

d=0.05m

$A=13*10^6m^2$

Volume $(V) = A*d = (15*10^6)(0.03) = 3.9*10^5m^3$

t = 3hours=10800s

$\rho = 1000kg/m^3$

From the given data we can calculate the volume of rain for 5 seconds

$V' = \frac{V}{t}*\Delta t_{total}$

Where,

$\Delta t_{total}$ It is the period of time we want to calculate total rainfall, that is

$V' = \frac{3.9*10^5}{10800}*5$

$V' = 1.805*10^2m^3$

Through water density we can now calculate the mass that fell during the 5 seconds:

$m' = V'*\rho$

$m' = 1.805*10^2*1000$

$m' = 1.805*10^5m^2$

Now applying the prevailing equation given we have to

$P=m'v$

$P = (1.805*10^5)(10)$

$P = 1.805*10^6 Kg.m/s$

Therefore the momentum of the rain that falls in five seconds is $1.805*10^6 Kg.m/s$

4 0

3 years ago

HELP ME, I'M BEING TIMED

m_a_m_a [10]

Answer:

i think c

Explanation:

because cars run on mechanical energy and solar powered means its by the sun which is light energy

7 0

3 years ago

Read 2 more answers