Answer:
the strength of the magnetic field inside the solenoid is 6.278 x 10⁻³ T.
Explanation:
Given;
length of the wire, = 34.9 m
length of solenoid, L = 0.24 m
radius of the solenoid, r = 0.051 m
current in the solenoid, I = 11.0 A
The number of turns of the wire is calculated as follow;
The strength of the magnetic field inside the solenoid is calculated as follows;
Therefore, the strength of the magnetic field inside the solenoid is 6.278 x 10⁻³ T.
