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3 years ago

What would happen if the poles of the magnet were reversed?

1 answer:

6 0

The direction of magnetic field lines get reversed as the direction of magnetic field lines is from north pole to south pole

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A wave of frequency 90 mega in 3 micro seconds. Calculate its wave length. hertz travels 6 km

gladu [14]

the wavelength is 2.2m

wavelength can be calculated by formula wavelength = velocity / frequency so here first we need to find the velocity so velocity is distance travelled/time taken that 2 X 10^8 m/s now wavelength is = 2 X 10^8/ 90=2.2m.

Waves are signals that can go through various media, including wire in the case of an electrical AC current, water, light, and other media. The separation between two identical points on a sinusoidal wave is known as the wavelength. You can determine how long there is between each wave's peak and each wave's trough if you know the frequency of the wave moving through the medium.

To learn more about wavelength:

brainly.com/question/13533093

#SPJ4

3 0

1 year ago

An inductor is connected across an ac source. suppose the frequency of the source is doubled. what happens to the inductive reac

MaRussiya [10]

<span>If an inductor is connected across an ac source and suppose the frequency of the source is doubled, then t</span>he inductive reactance of the inductor is also doubled. The inductive reactance (XL) is the t<span>he opposition to current flowing through a coil in an AC circuit, the </span>impedance measured in Ohms and can be calculated with the following formula:
XL=2*pi*f*L,
where f is the frequency. So, if the frequency is doubled than also the inductive reactance is doubled.

8 0

3 years ago

How do I solve this problem please help

frosja888 [35]

Answer:

som,eythiung did cant wait

Explanation:

ya so i texted maria and she said i con c()me over so letyeyey yeah betty letty

PAINN I MISS JUOICE WORLDD PAINNNN

7 0

2 years ago

which of the following could be considered a characteristic of draco's laws? a. liberal b. severe c. democratic d. fair

LiRa [457]

This is late af, but the answer is B. Severe

3 0

2 years ago

Read 2 more answers

A student sits on a rotating stool holding two 3.09-kg masses. When his arms are extended horizontally, the masses are 1.08 m fr

schepotkina [342]

Answer:

The New angular speed is $w_f = 2.034 rad/s$

The Kinetic energy before the masses are pulled in is $KE_i = 3.101 \ J$

The Kinetic energy after the masses are pulled in is $KE_f = 8.192 \ J$

Explanation:

From the we are told that masses are 1.08 m from the axis of rotation, this means that

The radius $r =1.08m$

The mass is $m = 3.09\ kg$

The angular speed $w = 0.770 \ rad/sec$

The moment of inertia of the system excluding the two mass $I = 3.25 \ kg \cdot m^2$

New radius $r_{new} = 0.34m$

Generally the conservation of angular momentum can be mathematical represented as

$w_f = [\frac{I_i}{I_f} ]w_i .....(1)$

Where $w_f$ is the final angular speed

$w_i$ is the initial angular speed

$I_i$ is the initial moment of inertia

$I_f$ is the final moment of inertia

Moment of inertia is mathematically represented as

$I = m r^2$

Where I is the moment of inertia

m is the mass

r is the radius

So the Initial moment of inertia is given as

$I_i = moment \ of \ inertia \ of\ the \ two \ mass \ + 3.25 \ kg \cdot m^2$

$I_i = 2m r^2 + 3.25$

The multiplication by is because we are considering two masses

$I_i = 2 [(3.09)(1.08)^2] +3.25 = 10.46 kg \cdot m^2$

So the final moment of inertia is given as

$I_f = 2[(3.09)(0.34)^2] +3.25 = 3.96 \ kg \cdot m^2$

Substituting these values into equation 1

$w_f = [\frac{10.46}{3.96} ] * 0.77 = 2.034 \ rad/sec$

Generally Kinetic energy is mathematically represented in term of moment of inertia as

$KE = \frac{1}{2} * I * w^2$

Now considering the kinetic energy before the masses are pulled in,

$KE_i = \frac{1}{2} * I_i * w^2_i$

The Moment of inertia would be $I_i = 10.46 \ Kg \cdot m^2$

The Angular speed would be $w_i = 0.77 \ rad/s$

Now substituting these value into the equation above

$KE_i = \frac{1}{2} * (10.46) * (0.770)^2 = 3.101 J$

Now considering the kinetic energy after the masses are pulled in,

$KE_f = \frac{1}{2} * I_f * w^2_f$

The Moment of inertia would be $I_f = 3.96 \ Kg \cdot m^2$

The Angular speed would be $w_f = 2.034 \ rad/s$

Now substituting these value into the equation above

$KE_f= \frac{1}{2} *(3.96)(2.034)^2$

$= 8.192J$

8 0

3 years ago