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zzz [600]
3 years ago
7

What would happen if the poles of the magnet were reversed?

Physics
1 answer:
erica [24]3 years ago
6 0
The direction of magnetic field lines get reversed as the direction of magnetic field lines is from north pole to south pole
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Ikg.
Tcecarenko [31]

Answer:

The mass of G1 at all times during this trial was <u>0.5</u> kg.

The velocity of G1 + G2 after the collision was <u>-1.24</u> m/s.

The momentum of G1 after the collision was <u>-2.10</u> kg · m/s.

Explanation:

i got it right

6 0
4 years ago
Describe how water may be treated before it is used by people?
slamgirl [31]
It can be purified or be used by a filter
5 0
3 years ago
Read 2 more answers
I NEED PHYSICS HELP? THE QUESTION IS IN THE PIC
Marina CMI [18]

Speed of the block at the bottom of the incline: 5.42 m/s

The first part of the problem can be solved by using the law of conservation of energy. Since the ramp is frictionless, the initial gravitational potential energy of the block at the top of the ramp is converted into kinetic energy at the bottom:

mgh = \frac{1}{2}mv^2 (1)

where

m is the mass of the block

g = 9.8 m/s^2 is the acceleration of gravity

h is the initial height of the block

v is the speed of the block at the bottom

The initial height of the block is equal to the height of the ramp, so

h=L sin \theta (2)

where

L = 3.00 m is the length of the ramp

\theta=30^{\circ} is the angle of the ramp

Substituting (2) into (1) and re-arranging the equation, we  find the speed

2gL sin \theta = v^2

v=\sqrt{2gL sin \theta}=\sqrt{2(9.8)(3.00)sin 30^{\circ}}=5.42 m/s

Coefficient of kinetic friction between the floor and the block: 0.3

In the second part of the motion, the block is slowed down by friction along the flat surface. According to the work-energy theorem, the work done by friction is equal to the change in kinetic energy of the block:

W=\Delta K=K_f -K_i

where

W is the work done by friction

Kf is the final kinetic energy of the block, which is zero since the block comes to rest

K_i = \frac{1}{2}mv^2 is the initial kinetic energy of the block, where

m = 10.0 kg is the mass of the block

v = 5.42 m/s is its initial speed

Substituting into the equation, we find

W=-\frac{1}{2}mv^2=-\frac{1}{2}(10.0)(5.42)^2=-146.9 J

and the work is negative, since the direction of the force of friction is opposite to the direction of motion of the block.

Now we can rewrite the work as the product between the force of friction and the displacement of the block:

W=-F_f d = - \mu mg d

where

\mu is the coefficient of friction

d = 5.00 m is the displacement of the block

Solving for \mu,

\mu = - \frac{W}{mgd}=-\frac{-146.9}{(10.0)(9.8)(5.00)}=0.3

4 0
3 years ago
fan can accelerate from the starting blocks to running 11 m/s down the track in 5 seconds. what is her acceleration?
Delvig [45]
At a discount furniture store, Chris offered a salesman $600 for a couch and a chair. The offer includes the 8% sales tax. If the salesman accepts the offer, what would be the price of the furniture, to the nearest dollar, before tax? Please show you work.
3 0
3 years ago
Read 2 more answers
Each plate of a parallel-plate air-filled capacitor has an area of 2×10−3 m2, and the separation of the plates is 5×10−2 mm. An
Alona [7]

Answer:

The surface charge density on the plate, \sigma=7.5\times 10^{-5}\ C/m^2

Explanation:

It is given that,

Area of parallel plate capacitor, A=2\times 10^{-3}\ m^2

Separation between the plates, d=5\times 10^{-2}\ mm

Electric field between the plates, E=8.5\times 10^{6}\ V/m

We need to find the surface charge density on the plates. The formula for electric field is given by :

E=\dfrac{\sigma}{\epsilon}

Where

\sigma = surface charge density

\sigma=E\times \epsilon

\sigma=8.5\times 10^{6}\ V/m\times 8.85\times 10^{-12}\ C^2/Nm^2

\sigma=0.000075\ C/m^2

\sigma=7.5\times 10^{-5}\ C/m^2

Hence, this is the required solution.

5 0
3 years ago
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