Answer:
The optimum wavelength = (8.863 × 10⁻⁷) m = 886.3 nm
Explanation:
The light that will generate the photovoltaic energy of 1.4 eV will must have that amount of energy
Energy of light waves is given as
E = hf
h = Planck's constant = (6.626 × 10⁻³⁴) J.s
f = Frequency of the light
The frequency is then further given as
f = (c/λ)
c = speed of light = (3.0 × 10⁸) m/s
λ = wavelength of the light = ?
E = (hc/λ)
λ = (hc/E)
Energy = E = 1.4 eV = 1.4 × 1.602 × 10⁻¹⁹ = (2.2428 × 10⁻¹⁹) J
λ = (6.626 × 10⁻³⁴ × 3.0 × 10⁸)/(2.2428 × 10⁻¹⁹)
λ = (8.863 × 10⁻⁷) m = 886 nm
Hope this Helps!!!
Since the object is dropped from some height so its initial speed must be zero
acceleration of the object is due to gravity
so we can use kinematics to find the time it will take to drop by x = 22 m
Now the speed after 2.12 s will be given as
so above is the speed and time
Answer:
Rutherford bombarded aluminum foil with beam of light known as alpha particles. The mass of this alpha particle is equivalent to helium atom.
Explanation:
Rutherford bombarded aluminum foil with beam of light known as alpha particles. The mass of this alpha particle is equivalent to helium atom.
When this alpha particles were made to strike the aluminum foil, some passed through the foil, some were reflected and speed others changed.
The ones reflected encountered heavier particle known as the nucleus, preventing them from passing through it. The whole observations indicated that atom is not is uniformly charged sphere as proposed by J.J Thomson.
Rutherford proposed new model known as the Planetary model of atom, which described atom as containing a nucleus which is revolved by electron, just like planets revolve round the sun. And this nucleus contains opposite charge to electron which is proton, to balance the motion.
Answer:
14 m/s
Explanation:
The motion of the stone is a free fall motion, so an accelerated motion with constant acceleration g = 9.8 m/s^2 towards the ground. So, we can use the following SUVAT equation:
where
v is the final speed of the stone as it reaches the water
u = 0 is the initial speed
g = 9.8 m/s^2 is the acceleration
h = 10 m is the distance covered by the stone
Solving for v, we find
I believe the answer is D. <span>The hypothesis is revised and another experiment is conducted.</span>
