The initial speed of car A is 15.18 m/s.
Momentum is defined as mass in motion. If there are two objects (the two objects in motion or only one object in motion and the other in stationary) that collide and no other forces work in the system, the law of momentum conservation applies in the system.
p=p'
pa+pb = pa'+pb'
(ma×va) + (mb×vb) = (ma×va') + (mb×vb')
- ma = mass of object A (kg) = 1,783 kg
- mb = mass of object B (kg) = 1,600 kg
- va = speed of object A before collides (m/s)
- va' = speed of object A after collides (m/s) = 8 m/s
- vb = speed of object B before collides (m/s) = 0 m/s
- vb' = speed of object B after collides (m/s) = 8 m/s
- p = momentum before collision (Ns)
- p' = momentum after collision (Ns)
(ma×va) + (mb×vb) = (ma×va') + (mb×vb')
(1,783×va) + (1,600×0) = (1,783×8) + (1,600×8)
(1,783×va) + 0 = 14,264+12,800
(1,783×va) = 27,064

va = 15.18 m/s
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5.2m/s
Explanation:
Given parameters:
Mass of baseball = 0.15kg
Momentum of baseball = 0.78kgm/s
Unknown:
Speed of baseball = ?
Solution:
The momentum of the baseball is a function of the product of the mass and velocity. It is a vector quantity:
Momentum = mass x velocity
Since the speed of the ball is unknown:
Velocity =
= 
= 5.2m/s
The speed of the baseball before it lands is 5.2m/s
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Answer: D. 0.29 m
Explanation:
We will use the following equations to describe the leap of the cat:
(1)
(2)
Where:
is the height of the cat
is the cat's initial velocity

is the acceleration due gravity
is the time
is the y-component of the velocity
Now the cat will have its maximum height
when
. So equation (2) is rewritten as:
(3)
Finding
:
(4)
(5)
(6)
Substituting (6) in (1):
(7)
Finally:
(8)
Answer:
J.J. Thomson discovered <u><em>the electron</em></u> by experimenting with a Crookes, or cathode ray, tube. He demonstrated that cathode rays were negatively charged. In addition, he also studied positively charged particles in neon gas.
Explanation:
the answer is the underlined part of the answer section. I hoped this helped you a lot!! Study hard for whatever you are doing!!
Answer:
✍️Argon:
†Observation:
»» Solid:
★ Temperature: 43 Kelvin.
★ Illustration: Particles are in one position not moving.
»» Liquid:
★ Temperature: 86 Kelvin
★ Illustration: Particles are still compacted but slightly moving.
»» Gas:
★ Temperature: 189 Kelvin
★ Illustration: Particles are moving slowly around each other.
Explanation: