Answer:
for the cellular respiration the human body needs 1.424 E21 molecules of glucose
Explanation:
mass glucose = 24 g
∴ Mw glucose = 180.156 g/mol
∴ 1 mol ≡ 6.022 E23 molecules
⇒ mol glucose = (24 g)×(mol/180.156 g) = 0.1332 mol glucose
⇒ molecules glucose = (0.1332 mol glucose)×(6.022 E23 molecules/mol)
⇒ molecules glucose = 1.424 E21 molecules
Answer:
4
Explanation:
Because of single replacement the ideal shape comes in form
Answer:
The second choice, or flammability.
Explanation:
The flammability of something is how easy it is for it to burn or ignite.
Answer:
161 mL
Explanation:
- Pb(NO₃)₂(aq) + Ba(OH)₂(aq) → Pb(OH)₂(s) + Ba(NO₃)₂(aq)
First we <u>calculate how many Pb⁺² moles reacted</u>, using the<em> given concentration and volume of the Pb(NO₃)₂ solution</em>:
- 163 mL * 0.656 M = 107 mmol Pb(NO₃)₂
As<em> 1 millimol of Pb(NO₃)₂ would react with 1 millimol of Ba(OH)₂,</em> to precipitate 107 mmoles of Pb(NO₃)₂ we would require 107 mmoles of Ba(OH)₂.
Using the number of moles and the concentration we can <u>calculate the required number of milliliters</u>:
- 0.666 M = 107 mmol / x mL
Mghcl14 + H2 = mghclh 16 work needed to solve this problem
