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boyakko [2]
3 years ago
14

Can someone help, please...? I really can't understand this...

Chemistry
1 answer:
barxatty [35]3 years ago
5 0
It’s okay to be a little intimidated by this but the answer is a lot more simple than it may look. All you have to do is multiply the standard enthalpies of formation with their stoichiometric coefficient for every chemical and subtract the reactants from the products:

6(-393.5) + 3(-285.8) -1(49) -15(0)
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What is the empirical formula of a compound that contains 6.10 g of hydrogen and 28 g of nitrogen?
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Answer:

NH₃

Explanation:

mass H = 6.10 grams

mass N = 28.00 grams

mass cpd = (6.10 + 28.00)grams = 34.10 grams

%H/100wt = (6.10/34.10)100% = 17.9% w/w

%N/100wt = (28.00/34.1)100% = 82.1% w/w

%/100wt => grams/100wt => moles => ratio => reduce => emp ratio

%H/100wt = 17.9% w/w => 17.9g => (17.9/1)moles = 17.9 moles H

%N/100wt = 82.1% w/w => 82.1g => (82.1/14)moles = 5.9 moles N

Ratio N:H => 17.9 : 5.9

Reduce mole ratio (divide by smaller mole value) => 17.9/5.9 : 5.9/5.9

=> 3HY:1H empirical ratio => empirical formula NH₃ (ammonia)

3 0
3 years ago
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The smallest functional and structural unit of an organism, usually microscopic and consisting of cytoplasm and a nucleus in a membrane.

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Thus the atomic mass = 3  +  4
  
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