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FromTheMoon [43]
3 years ago
7

Hey I’ve been struggling to find the answer for this question Factorise 7-14n

Mathematics
1 answer:
FromTheMoon [43]3 years ago
6 0

Answer:

7(1-2n)

Step-by-step explanation:

7-14n

Rewrite

7*1 - 7*2n

Factor

7(1-2n)

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Helpppppppppppppppppp meeeeeeeeeeeeeeeeeee
DanielleElmas [232]

The fraction computed shows that the cups of sugar that can be used based on the flour will be B. 4 1/2 cups.

<h3>How to calculate the fraction?</h3>

From the information, Jonah used 1 1/2 cups of brown sugar and 2 1/3 cups for flour.

Therefore, the cups of sugar needed will be:

= 1.5/2.33 × 7

= 4.5 = 4 1/2.

Learn more about fractions on:

brainly.com/question/78672

#SPJ1

4 0
2 years ago
Use any of the methods to determine whether the series converges or diverges. Give reasons for your answer.
Aleks [24]

Answer:

It means \sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6} also converges.

Step-by-step explanation:

The actual Series is::

\sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6}

The method we are going to use is comparison method:

According to comparison method, we have:

\sum_{n=1}^{inf}a_n\ \ \ \ \ \ \ \ \sum_{n=1}^{inf}b_n

If series one converges, the second converges and if second diverges series, one diverges

Now Simplify the given series:

Taking"n^2"common from numerator and "n^6"from denominator.

=\frac{n^2[7-\frac{4}{n}+\frac{3}{n^2}]}{n^6[\frac{12}{n^6}+2]} \\\\=\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{n^4[\frac{12}{n^6}+2]}

\sum_{n=1}^{inf}a_n=\sum_{n=1}^{inf}\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\ \ \ \ \ \ \ \ \sum_{n=1}^{inf}b_n=\sum_{n=1}^{inf} \frac{1}{n^4}

Now:

\sum_{n=1}^{inf}a_n=\sum_{n=1}^{inf}\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\\ \\\lim_{n \to \infty} a_n = \lim_{n \to \infty}  \frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\\=\frac{7-\frac{4}{inf}+\frac{3}{inf}}{\frac{12}{inf}+2}\\\\=\frac{7}{2}

So a_n is finite, so it converges.

Similarly b_n converges according to p-test.

P-test:

General form:

\sum_{n=1}^{inf}\frac{1}{n^p}

if p>1 then series converges. In oue case we have:

\sum_{n=1}^{inf}b_n=\frac{1}{n^4}

p=4 >1, so b_n also converges.

According to comparison test if both series converges, the final series also converges.

It means \sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6} also converges.

5 0
3 years ago
What is 7 1/2 divided 3/4
frosja888 [35]

Answer:

10

Step-by-step explanation:

4 0
3 years ago
What is the volume of a cone that has a radius of 4 cm and a height of 9 cm?
vodka [1.7K]
For any sort of pyramid or cone, the volume is 1/3 of the volume of a prism with the same base and height. Since the volume of a prism/cylinder is V=Bh, the volume of a pyramid/cone is V=\frac{1}3Bh.

In this case, our base is a circle, which has a radius of 4 cm.
The area of a circle is A=\pi r^2 where r is the radius.
A=\pi (4)^2=\pi (4\times4)=16\pi=B

We now know that our base is 16π cm.
We also know that our height is 9 cm.
Let's plug these into our volume formula.

V=\frac{1}3\times16\pi \times9

Use 3.14 to approximate pi as the question states. 16 × 3.14 = 50.24.

V\approx\frac{1}3\times50.24\times9

We could punch all of that into our calculator to get the same answer, but since 1/3 of 9 is clearly 3, let's just go with that.

V\approx3\times50.24

\boxed{V\approx150.72\ cm^3}
8 0
3 years ago
Read 2 more answers
Is Triangle B a rotation of Triangle A? Explain how you know.
Natasha_Volkova [10]

Answer:

where is the figure

Step-by-step explanation:

5 0
3 years ago
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