1. Name the compound present in a sample of dry air.
1 answer:
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Answer : The pH of the solution is, 9.63
Explanation : Given,
The dissociation constant for HCN =
First we have to calculate the moles of HCN and NaCN.
and,
The balanced chemical reaction is:
Initial moles 0.1116 0.0461 0.08978
At eqm. (0.1116-0.0461) 0 (0.08978+0.0461)
0.0655 0.1359
Now we have to calculate the pH of the solution.
Using Henderson Hesselbach equation :
Now put all the given values in this expression, we get:
Therefore, the pH of the solution is, 9.63