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3 years ago

What is Applied chemisrty??

Chemistry

1 answer:

VikaD [51]3 years ago

8 0

Answer:

Applied Chemistry is the scientific field for understanding basic chemical properties of materials and for producing new materials with well-controlled functions. (:

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which state of matter would be described as having highly energized charged particles which move extremely fast

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The answer is "plasma" my dude

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How many atoms are in the following: 3Ca3(PO4)2? A 3 B)9 С)13 D) 39

irina1246 [14]

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Explanation:

i feel in my gut its the right answer

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3 years ago

Given these reactions, where X represents a generic metal or metalloid 1 ) H 2 ( g ) + 1 2 O 2 ( g ) ⟶ H 2 O ( g ) Δ H 1 = − 241

anygoal [31]

Answer : The enthalpy of the given reaction will be, -1048.6 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

The main reaction is:

$XCl_4(s)+2H_2O(l)\rightarrow XO_2(s)+4HCl(g)$ $\Delta H=?$

The intermediate balanced chemical reactions are:

(1) $H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(g)$ $\Delta H_1=-241.8kJ$

(2) $X(s)+2Cl_2(g)\rightarrow XCl_4(s)$ $\Delta H_2=+461.9kJ$

(3) $\frac{1}{2}H_2(g)+\frac{1}{2}Cl_2(g)\rightarrow HCl(g)$ $\Delta H_3=-92.3kJ$

(4) $X(s)+O_2(g)\rightarrow XO_2(s)$ $\Delta H_4=-789.1kJ$

(5) $H_2O(g)\rightarrow H_2O(l)$ $\Delta H_5=-44.0kJ$

Now reversing reaction 2, multiplying reaction 3 by 4, reversing reaction 1 and multiplying by 2, reversing reaction 5 and multiplying by 2 and then adding all the equations, we get :

(1) $2H_2O(g)\rightarrow 2H_2(g)+O_2(g)$ $\Delta H_1=2\times 241.8kJ=483.6kJ$

(2) $XCl_4(s)\rightarrow X(s)+2Cl_2(g)$ $\Delta H_2=-461.9kJ$

(3) $2H_2(g)+2Cl_2(g)\rightarrow 4HCl(g)$ $\Delta H_3=4\times -92.3kJ=-369.2kJ$

(4) $X(s)+O_2(g)\rightarrow XO_2(s)$ $\Delta H_4=-789.1kJ$

(5) $2H_2O(l)\rightarrow 2H_2O(g)$ $\Delta H_5=2\times 44.0kJ=88.0kJ$

The expression for enthalpy of main reaction will be:

$\Delta H=\Delta H_1+\Delta H_2+\Delta H_3+\Delta H_4+\Delta H_5$

$\Delta H=(483.6)+(-461.9)+(-369.2)+(-789.1)+(88.0)$

$\Delta H=-1048.6kJ$

Therefore, the enthalpy of the given reaction will be, -1048.6 kJ

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3 years ago

Help one number 46 please

Juli2301 [7.4K]

Say the dereference between the two is that "Exo" means "outside" and "Endo" means "inside" meaning one pulls heat inside (endothermic) and the other expels heat (exothermic)

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3 years ago

Classify each titration curve as representing a strong acid titrated with a strong base, a strong base titrated with a strong ac

Leona [35]

From left to right:

1) starts at high pH, no buffer zone - strong base being titrated with strong acid
2) starts at low pH, no buffer zone - strong acid being titrated with strong base
3) starts at low pH, shows a buffer zone - weak acid titrated with strong base
4) starts at high pH, shows a buffer zone - weak base titrated with strong acid
5) polyprotic due to two equivalence points

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3 years ago

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What is Applied chemisrty??​

What is Applied chemisrty??