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olga55 [171]
3 years ago
8

This is agree or disagree I need help ASAP!!

Chemistry
2 answers:
PIT_PIT [208]3 years ago
8 0
All of them are agree :)
soldi70 [24.7K]3 years ago
8 0
I’m pretty sure all of them are agree
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Socratic an example of an atom that has no charge is one that has
aksik [14]

An example of an atom that has no charge is one that has a. 2 protons, 2 electrons, and 1 neutron.

To be neutral an atom must have the <em>same number</em> of protons (+) and electrons (-).

Only then will the <em>charges cancel</em> and give a neutral atom.


5 0
4 years ago
Please help me! Thank you
Marta_Voda [28]
The reaction is exothermic, the energy in the bonds has been released to the surroundings (causing the potential energy to go down). The increase in energy in the surrounding heats them up hence exothermic.
5 0
4 years ago
Read 2 more answers
0.158 g of a mystery molecule is placed into a bomb calorimeter that has a heat capacity of 1650 J/C. After the sample is combus
Lunna [17]

<u>Answer:</u> The molar mass of the mystery element is 111.27 g/mol

<u>Explanation:</u>

To calculate the heat absorbed by the calorimeter, we use the equation:

q=c\Delta T

where,

q = heat absorbed

c = heat capacity of calorimeter = 1650 J/°C

\Delta T = change in temperature = 2.54^oC

Putting values in above equation, we get:

q=1650J/^oC\times 2.54^oC=4191kJ

Heat absorbed by the calorimeter will be equal to the heat released by the reaction.

<u>Sign convention of heat:</u>

When heat is absorbed, the sign of heat is taken to be positive and when heat is released, the sign of heat is taken to be negative.

To calculate the number of moles of the mystery molecule, we use the equation:

\Delta H_{rxn}=\frac{q}{n}

where,

q = amount of heat released = -4191 J

n = number of moles = ? moles

\Delta H_{rxn} = enthalpy change of the reaction = -2960 kJ/mol = -2960000 J/mol    (Conversion factor = 1 kJ = 1000 J)

Putting values in above equation, we get:

-2960000=\frac{-4191J}{n}\\\\n=\frac{-4191}{-2960000}=0.00142mol

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of mystery molecule = 0.158 g

Moles of mystery molecule = 0.00142 mol

Putting values in above equation, we get:

0.00142mol=\frac{0.158g}{\text{Molar mass of mystery molecule}}\\\\\text{Molar mass of mystery molecule}=\frac{0.158}{0.00142}=111.27g/mol

Hence, the molar mass of the mystery element is 111.27 g/mol

8 0
3 years ago
Which notation represents the largest atomic radius?<br><br> Cl<br><br> F<br><br> F−<br><br> Cl−
hichkok12 [17]

Answer:

Cl⁻

Explanation:

Definition of atomic radii

The atomic radius is the distance between center of two bonded atoms.

Trend along period:

As we move from left to right across the periodic table the number of valance electrons in an atom increase.The atomic size tend to decrease in same period of periodic table because the electrons are added with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. The positive charge is going to increase and this charge is greater in effect than the charge of electrons. This effect lead to the greater nuclear attraction. The electrons are pull towards the nucleus and valance shell get closer to the nucleus. As a result of this greater nuclear attraction atomic radius decreases.

Trend along group:

In group by addition of electron atomic radii increase from top to bottom due to increase in atomic number and addition of extra shell.

In this way Cl⁻ will have the largest atomic radii because one extra electron is added and its atomic number is already greater than fluorine.

5 0
4 years ago
When 3.4 moles of hydrogen gas react with excess oxygen how many moles of water will be produced
s344n2d4d5 [400]
1. start with balanced equation.
2 H2(g) + O2(g<span>) </span><span> 2 H</span>2O(g<span>)
</span>
2. Use stoichiometry 
(3.4moles of H)(2moles of H2O/2moles of H)
The moles of H will cancel, leaving you with moles of H2O. 
The answer is 3.4 moles of H2O
6 0
4 years ago
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