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Olin [163]
4 years ago
13

You have a solution suspected to contain copper(II) ions, barium ions, or iron ions. Which of the following solutions might be a

dded to determine which cation is present?
(A) ammonium nitrate
(B) potassium sulfate
(C) sodium acetate
(D) sodium chloride
(E) zinc bromide
Chemistry
1 answer:
Charra [1.4K]4 years ago
5 0

Answer:

potassium sulfate

Explanation:

To determine the cation present, a reagent is added which is able to precipitate one of the suspected cations. This will confirm the presence of that cation or disprove it all together. It is known that sulphates of group 2 elements are insoluble in water. When potassium sulfate is added, barium sulphate will be removed from solution as a white precipitate thus confirming that the solution contains barium ions.

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There are several ways that a mutation may occur. Which of the following is not a way for a mutation to occur during the DNA rep
Umnica [9.8K]

Answer:

D. An entire gene may be reversed

3 0
3 years ago
Read 2 more answers
To what volume should you dilute 60.0 mL of a 4.50 M KI solution so that 30.0 mL of the diluted solution contains 3.25 g of KI?
SpyIntel [72]

Answer:

You should dilute to 414.1 mL

Explanation:

Let's apply the dilution formula to solve this:

M conc . Vol conc = M dil . Vol dil

Molarity for concentrated solution → 4.50 M

Volume for concentrated solution → 60 mL

Molarity for diluted solution → Unknown

Volume for diluted solution → Answer

Let's determine the molarity for diluted solution with data given.

We convert the mass of KI to moles

3.25 g . 1 mol/166 g = 0.0195 moles

Let's convert the volume from mL to L

30 mL . 1 L/1000mL = 0.030 L

Molarity (mol/L) = 0.0195 mol /0.030L = 0.652 M

We replace the data in the formula

4.50 M . 60 mL = 0.652 M . Volume for diluted solution

(4.50M . 60mL) / 0.652M = Volume for diluted solution

414.1 mL = Volume for diluted solution

7 0
3 years ago
Read 2 more answers
A 32.2 g iron rod, initially at 21.9 C, is submerged into an unknown mass of water at 63.5 C. in an insulated container. The fin
lorasvet [3.4K]

Answer : The mass of the water in two significant figures is, 3.0\times 10^1g

Explanation :

In this case the heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of iron metal = 0.45J/g^oC

c_2 = specific heat of water = 4.18J/g^oC

m_1 = mass of iron metal = 32.3 g

m_2 = mass of water = ?

T_f = final temperature of mixture = 59.2^oC

T_1 = initial temperature of iron metal = 21.9^oC

T_2 = initial temperature of water = 63.5^oC

Now put all the given values in the above formula, we get

32.3g\times 0.45J/g^oC\times (59.2-21.9)^oC=-m_2\times 4.18J/g^oC\times (59.2-63.5)^oC

m_2=30.16g\approx 3.0\times 10^1g

Therefore, the mass of the water in two significant figures is, 3.0\times 10^1g

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3 years ago
Pleas help me i have to submit homework i hour<br> i will mark brainliest
steposvetlana [31]

Answer:

I can help

Explanation:

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6 0
3 years ago
Which two functional groups react to form an easter linkage?
7nadin3 [17]

Answer: You know that monomers that are joined by condensation polymerization have two functional groups. You also know (from Part 6) that a carboxylic acid and an amine can form an amide linkage, jand a carboxylic acid and an alcohol can form an ester linkage.

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3 years ago
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