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Olin [163]
4 years ago
13

You have a solution suspected to contain copper(II) ions, barium ions, or iron ions. Which of the following solutions might be a

dded to determine which cation is present?
(A) ammonium nitrate
(B) potassium sulfate
(C) sodium acetate
(D) sodium chloride
(E) zinc bromide
Chemistry
1 answer:
Charra [1.4K]4 years ago
5 0

Answer:

potassium sulfate

Explanation:

To determine the cation present, a reagent is added which is able to precipitate one of the suspected cations. This will confirm the presence of that cation or disprove it all together. It is known that sulphates of group 2 elements are insoluble in water. When potassium sulfate is added, barium sulphate will be removed from solution as a white precipitate thus confirming that the solution contains barium ions.

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If the ph of a solution is decreased from ph 8 to ph 6 it means that the
saw5 [17]

Explanation:

Relation between pH and concentration of hydrogen ions is as follows.

                  pH = -log [H^{+}]

So, it means that an increase in the value of pH will show that there occurs a decrease in concentration of hydrogen ions.

Therefore, the solution becomes basic in nature.

On the other hand, a decrease in the value of pH will show that there occurs an increase in the concentration of hydrogen ions.

Therefore, the solution becomes more acidic in nature.

Hence, if the pH of a solution is decreased from pH 8 to pH 6 it means that the concentration of hydrogen ions has increased in the solution.

5 0
3 years ago
Read 2 more answers
A ____________ star would have the hottest surface temperature.
Alexandra [31]

Answer:

Blue

Explanation:

If you look at a flame, blue is always at the bottom right? So that would be common sense that blue would be the hottest.

7 0
3 years ago
Read 2 more answers
ΔU for a van der Waals gas increases by 475 J in an expansion process, and the magnitude of w is 93.0 J.
timofeeve [1]

Complete question:

ΔU for a van der Waals gas increases by 475 J in an expansion process, and the magnitude of w is 93.0 J. calculate the magnitude of q for the process.

Answer:

The magnitude of q for the process 568 J.

Explanation:

Given;

change in internal energy of the gas, ΔU = 475 J

work done by the gas, w = 93 J

heat added to the system, = q

During gas expansion process, heat is added to the gas.

Apply the first law of thermodynamic to determine the magnitude of heat added to the gas.

ΔU = q - w

q = ΔU +  w

q = 475 J  +  93 J

q = 568 J

Therefore, the magnitude of q for the process 568 J.

6 0
3 years ago
Be sure to answer all parts. Consider the reaction A + B → Products From the following data obtained at a certain temperature, d
worty [1.4K]

Answer : The order of reaction with respect to A is, first order reaction.

The order of reaction with respect to B is, zero order reaction.

The overall order of reaction is, first order reaction.  

Explanation :

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

A+B\rightarrow Products

Rate law expression for the reaction:

\text{Rate}=k[A]^a[B]^b

where,

a = order with respect to A

b = order with respect to B

Expression for rate law for first observation:

3.20\times 10^{-1}=k(1.50)^a(1.50)^b ....(1)

Expression for rate law for second observation:

3.20\times 10^{-1}=k(1.50)^a(2.50)^b ....(2)

Expression for rate law for third observation:

6.40\times 10^{-1}=k(3.00)^a(1.50)^b ....(3)

Dividing 1 from 2, we get:

\frac{3.20\times 10^{-1}}{3.20\times 10^{-1}}=\frac{k(1.50)^a(2.50)^b}{k(1.50)^a(1.50)^b}\\\\1=1.66^b\\b=0

Dividing 1 from 3, we get:

\frac{6.40\times 10^{-1}}{3.20\times 10^{-1}}=\frac{k(3.00)^a(1.50)^b}{k(1.50)^a(1.50)^b}\\\\2=2^a\\a=1

Thus, the rate law becomes:

\text{Rate}=k[A]^1[B]^0

\text{Rate}=k[A]

Thus,

The order of reaction with respect to A is, first order reaction.

The order of reaction with respect to B is, zero order reaction.

The overall order of reaction is, first order reaction.

7 0
3 years ago
4
STALIN [3.7K]

Answer: The space occupied by the gas at 400 torr and 25^{o}C is 250 mL.

Explanation:

Given: V_{1} = 250 mL,    P_{1} = 800 torr,     T_{1} = 50^{o}C

V_{2} = ?,         P_{2} = 400 torr,        T_{2} = 25^{o}C

Formula used is as follows.

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}

Substitute the values into above formula as follows.

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{800 torr \times 250 mL}{50^{o}C} = \frac{400 torr \times V_{2}}{25^{o}C}\\V_{2} = 250 mL

Thus, we can conclude that space occupied by the gas at 400 torr and 25^{o}C is 250 mL.

7 0
3 years ago
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