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Olin [163]
3 years ago
13

You have a solution suspected to contain copper(II) ions, barium ions, or iron ions. Which of the following solutions might be a

dded to determine which cation is present?
(A) ammonium nitrate
(B) potassium sulfate
(C) sodium acetate
(D) sodium chloride
(E) zinc bromide
Chemistry
1 answer:
Charra [1.4K]3 years ago
5 0

Answer:

potassium sulfate

Explanation:

To determine the cation present, a reagent is added which is able to precipitate one of the suspected cations. This will confirm the presence of that cation or disprove it all together. It is known that sulphates of group 2 elements are insoluble in water. When potassium sulfate is added, barium sulphate will be removed from solution as a white precipitate thus confirming that the solution contains barium ions.

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How many moles of mgs2o3 are in 193 g of the compound?
Mashutka [201]

Answer:

             1.414 Moles

Solution:

Data Given:

                 Mass of MgS₂O₃  =  193 g

                 M.Mass of MgS₂O₃  =  136.43 g.mol⁻¹

                 Moles  =  ?

Formula Used:

                            Moles  =  Mass ÷ M.Mass

Putting values,

                            Moles  =  193 g ÷ 136.43 g.mol⁻¹

                            Moles =  1.414 mol

8 0
3 years ago
A compound contains sulfur, oxygen, and chlorine. Analysis shows that it contains by mass 26.95% sulfur and 59.61% chlorine. Wha
sladkih [1.3K]

Answer:

SCl₂

Explanation:

In order to know the empirical formula, we have to follow a series of steps.

Step 1: Divide each percentage by the atomic mass

S: 26.95/32.07 = 0.8403

Cl: 59.61/35.45 = 1.682

Step 2: Divide all the numbers by the smallest one.

S: 0.8403/0.8403 = 1

Cl: 1.682/0.8403 ≈ 2

The empirical formula of the compound is SCl₂.

7 0
3 years ago
Read 2 more answers
HELP IM AB TO CRY
Lemur [1.5K]

Answer:

1.23 × 10³ N

Explanation:

Step 1: Given and required data

  • Mass of the person (m): 125 kg
  • Acceleration due to the gravitational force (g): 9.81 m/s²

Step 2: Calculate the force acting between the Earth and a 125-kg person standing on the surface of the Earth

We will use Newton's second law of motion.

F = m × g

F = 125 kg × 9.81 m/s²

F = 1.23 × 10³ N

8 0
3 years ago
If the temperature of an object is 335K,how would his be expressed on the celsius scale ?
IRISSAK [1]
335K would be expressed as 61.85 degrees Celsius  
3 0
3 years ago
Read 2 more answers
A student in chemistry 150-02 weighed out 55.5 g of octane (C8H18) and allowed it to react with oxygen, O2. The products formed
Anni [7]

Answer:

Explanation:

Given data:

Mass of octane = 55.5 g

Balanced chemical equation = ?

Mass of oxygen required to react  = ?

Mass of CO₂ for med = ?

Molecules of water produced = ?

Mass of octane required to produced 30.0 g of water = ?

Solution:

1)

Chemical equation:

2C₈H₁₈ + 25O₂     →  16CO₂ + 18H₂O

2)

Mass of oxygen required to react  = ?

Mass of octane = 55.0 g

Solution:

Number of moles of octane:

Number of moles = mass/ molar mass

Number of moles = 55.0 g/114.23 g/mol

Number of moles = 0.48 mol

Now we will compare the moles of octane with oxygen.

                        C₈H₁₈          :           O₂

                           2              :            25

                         0.48          :          25/2×0.48 = 6 mol

Mass of oxygen required:

Mass = number of moles × molar mass

Mass = 6 mol × 32 g/mol

Mass = 192 g

3)

Given data:

Mass of carbon dioxide produced = ?

Mass of octane = 55g

Solution:

Number of moles of octane:

Number of moles = mass/ molar mass

Number of moles = 55.0 g/114.23 g/mol

Number of moles = 0.48 mol

Now we will compare the moles of octane with CO₂.

                        C₈H₁₈          :           CO₂

                           2              :            16

                         0.48          :          16/2×0.48 = 3.84 mol

Mass of CO₂ produced:

Mass = number of moles × molar mass

Mass = 3.84 mol × 44 g/mol

Mass = 168.96 g

4)

Given data:

Molecules of water produced = ?

Mass of octane = 55g

Solution:

Number of moles of octane:

Number of moles = mass/ molar mass

Number of moles = 55.0 g/114.23 g/mol

Number of moles = 0.48 mol

Now we will compare the moles of octane with H₂O.

                        C₈H₁₈          :           H₂O

                           2              :            18

                         0.48          :          18/2×0.48 = 4.32 mol

Number  of molecules of water:

1 mol = 6.022× 10²³ molecules

4.32 mol × 6.022× 10²³ molecules/ 1 mol

26 × 10²³ molecules

5)

Given data:

Mass of octane required = ?

Mass of water produced = 30 g

Solution:

Number of moles of water.

Number of moles = mass/ molar mass

Number of moles = 30 g/ 18 gmol

Number  of moles = 1.67 mol

Now we will compare the moles of water and octane from balance chemical equation:

2C₈H₁₈ + 25O₂     →  16CO₂ + 18H₂O

                 

H₂O        :         C₈H₁₈

 18          :          2

 1.67       :       2/18×1.67 = 0.185 mol

Mass of octane:

Mass = number of moles ×molar mass

Mass = 0.185 × 114.23 g/mol

Mass = 21.13 g

5 0
3 years ago
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