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mariarad [96]
3 years ago
13

If cacl2 is dissolved in water, what can be said about the concentration of the ca2+ ion? view available hint(s) if is dissolved

in water, what can be said about the concentration of the ion? it has the same concentration as the cl− ion. its concentration is half that of the cl− ion. its concentration is twice that of the cl− ion. its concentration is one-third that of the cl− ion.
Chemistry
2 answers:
Simora [160]3 years ago
8 0
The concentration of Ca2+ ions is half that of the Cl- ions.
Furkat [3]3 years ago
6 0

<u>Answer:</u> The correct answer is its concentration is half that of the Cl^- ion.

<u>Explanation:</u>

We are given a chemical compound having formula CaCl_2

It is an ionic compound because it is formed by the combination of Ca^{2+}\text{ and }Cl^- ion

When an ionic compound is dissolved in water, it breaks into its ions. The chemical equation for the ionization of calcium chloride follows:

CaCl_2\rightarrow Ca^{2+}+2Cl^-

By stoichiometry of the reaction:

1 mole of calcium chloride produces 1 mole of calcium ions and 2 moles of chloride ions

From above, it is visible that number of chloride ions is twice that of calcium ion and so will be its concentration.

Thus, the concentration of calcium ions will be half that of chloride ions.

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2 years ago
Why is potassium nitrate classified as aj electrolyte?
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6 0
3 years ago
Read 2 more answers
A 0.652-g sample of a pure strontium halide reacts with excess sulfuric acid. the solid strontium sulfate formed is separated, d
seraphim [82]

Answer:

The formula of the original halide is SrCl₂.

Explanation:

  • The balanced equation of this reaction is:

SrX₂ + H₂SO₄ → SrSO₄ + 2 HX, where X is the halide.

  • From the equation stichiometry, 1.0 mole of strontium halide will result in 1.0 mole of SrSO₄.
  • The number of moles of SrSO₄ <em>(n = mass/molar mass) </em>= (0.755 g) / (183.68 g/mole) = 4.11 x 10⁻³ mole.
  • The number of moles of SrX are  4.11 x 10⁻³ moles from the stichiometry of the balanced equation.
  • n = mass / molar mass, n =  4.11 x 10⁻³ moles and mass = 0.652 g.
  • The molar mass of SrX₂ = mass / n = (0.652) / (4.11 x 10⁻³ moles) = 158.62 g/mole.
  • The molar mass of SrX₂ (158.62 g/mole) = Atomic mass of Sr (87.62 g/mole) + (2 x Atomic mass of halide X).
  • The atomic mass of halide X = (158.62 g/mole) - (87.62 g/mole) / 2 = 71 / 2  g/mole = 35.5 g/mole.
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4 0
3 years ago
Determine the volume in liters occupied by 22.6 g of I2 gas at STP.
AleksandrR [38]

 The volume in liters  occupied  by 22.6 g  of I₂  gas  at STP  is  1.99 L (answer A)

 <u><em>calculation</em></u>

Step: find the  moles of I₂

moles= mass÷  molar mass

from  periodic table the  molar mass  of I₂  is  253.8 g/mol

moles = 22.6 g÷253.8 g/mol =0.089 moles

Step 2:find the volume  of I₂  at STP

At STP  1  moles =22.4 L

         0.089 moles= ? L

<em>by cross  multiplication</em>

={ (0.089 moles x 22.4 L) /1 mole} = 1.99 L


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